Windows – Extract a certain file from an archive with 7-Zip from the command line

I was in the same situation when backing up a 12GB directory.

I fixed it by using the ditto command which was readily available with the OS X Yosemite installation:

ditto -x -k file.zip dst-directory

-x to extract an archive    
-k Specifies it to be a PKZip archive instead of the default CPIO    

EDIT Given: Using batch script.

You may wish to use a third party zip tool (highly recommend 7-ZIP command line version called 7z.exe) to accomplish this.

with 7z, the syntax is as follows:

7z <command> [<switch>...] <base_archive_name> [<arguments>...]

To extract the command would be:

7z e file.zip -y

the -y switch assume "Yes" answer to any questions that may come up during extraction such as overwrite requests.

So your command will read

CD "C:\Location\Of\ZipFiles"
FOR /F "USEBACKQ tokens=*" %%F IN (`DIR /b *.zip`) DO (7z e "%%F" -y)

If you want to output them into a different location, you can use the -o switch and specify the directory:

7z e "%%F" -y -oC:\Some\Other\Folder\

EDIT:

To perform the extract with full paths and specifying all ZIP archives only, use this:

7z x -tzip "C:\Location\of\zips\*"

Or even nutzier... all ZIP files on C: drive:

7z x -r -tzip "C:\*"

EDIT2:

Making it compatible with your output file, this:

dir /s /b *.zip > allzips.txt
for /F %%x in (allzips.txt) do (7z x -tzip "%%x")