7-Zip command line to extract a folder from an archive

Doh! I really should have looked harder for an answer.

From the 7-Zip FAQ:

Why does drag-and-drop archive extraction from 7-Zip to Explorer use temp files?

7-Zip doesn't know folder path of drop target. Only Windows Explorer knows exact drop target. And Windows Explorer needs files (drag source) as decompressed files on disk. So 7-Zip extracts files from archive to temp folder and then 7-Zip notifies Windows Explorer about paths of these temp files. Then Windows Explorer copies these files to drop target folder.

To avoid temp file usage, you can use Extract command of 7-Zip or drag-and-drop from 7-Zip to 7-Zip.

EDIT Given: Using batch script.

You may wish to use a third party zip tool (highly recommend 7-ZIP command line version called 7z.exe) to accomplish this.

with 7z, the syntax is as follows:

7z <command> [<switch>...] <base_archive_name> [<arguments>...]

To extract the command would be:

7z e file.zip -y

the -y switch assume "Yes" answer to any questions that may come up during extraction such as overwrite requests.

So your command will read

CD "C:\Location\Of\ZipFiles"
FOR /F "USEBACKQ tokens=*" %%F IN (`DIR /b *.zip`) DO (7z e "%%F" -y)

If you want to output them into a different location, you can use the -o switch and specify the directory:

7z e "%%F" -y -oC:\Some\Other\Folder\

EDIT:

To perform the extract with full paths and specifying all ZIP archives only, use this:

7z x -tzip "C:\Location\of\zips\*"

Or even nutzier... all ZIP files on C: drive:

7z x -r -tzip "C:\*"

EDIT2:

Making it compatible with your output file, this:

dir /s /b *.zip > allzips.txt
for /F %%x in (allzips.txt) do (7z x -tzip "%%x")