That's an odd request!
I'd use find
+ awk
to grab a file in the deepest directory:
bash-3.2$ deepest=$(find / -type f | awk -F'/' 'NF > depth {
> depth = NF;
> deepest = $0;
> }
>
> END {
> print deepest;
> }')
Using ${deepest}
in your mv
command is left as an exercise but the following five lines may help you further:
bash-3.2$ echo "${deepest}"
/Developer/SDKs/MacOSX10.6.sdk/System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/gems/1.8/gems/activesupport-2.3.5/lib/active_support/vendor/tzinfo-0.3.12/tzinfo/definitions/America/Argentina/Buenos_Aires.rb
bash-3.2$ echo "${deepest%.*}"
/Developer/SDKs/MacOSX10.6.sdk/System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/gems/1.8/gems/activesupport-2.3.5/lib/active_support/vendor/tzinfo-0.3.12/tzinfo/definitions/America/Argentina/Buenos_Aires
bash-3.2$ echo "${deepest%/*}"
/Developer/SDKs/MacOSX10.6.sdk/System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/gems/1.8/gems/activesupport-2.3.5/lib/active_support/vendor/tzinfo-0.3.12/tzinfo/definitions/America/Argentina
bash-3.2$ echo "${deepest##*/}"
Buenos_Aires.rb
bash-3.2$ echo "${deepest##*.}"
rb
Following update to question:
find -type d
[...] "This would only find the directory. [...] How could this be solved in the most simple way?".
By supplying -type f
to find
to find all files (f
), not all directories (d
).
To get the same output you note in your question, all that is needed is this:
PS1='${PS2c##*[$((PS2c=0))-9]}- > '
PS2='$((PS2c=PS2c+1)) > '
You need not contort. Those two lines will do it all in any shell that pretends to anything close to POSIX compatibility.
- > cat <<HD
1 > line 1
2 > line $((PS2c-1))
3 > HD
line 1
line 2
- > echo $PS2c
0
But I liked this. And I wanted to demonstrate the fundamentals of what makes this work a little better. So I edited this a little. I stuck it in /tmp
for now but I think I'm going to keep it for myself, too. It's here:
cat /tmp/prompt
PROMPT SCRIPT:
ps1() { IFS=/
set -- ${PWD%"${last=${PWD##/*/}}"}
printf "${1+%c/}" "$@"
printf "$last > "
}
PS1='$(ps1)${PS2c##*[$((PS2c=0))-9]}'
PS2='$((PS2c=PS2c+1)) > '
Note: having recently learned of yash, I built it yesterday. For whatever reason it doesn't print the first byte of every argument with the %c
string - though the docs were specific about wide-char extensions for that format and so it maybe related - but it does just fine with %.1s
That's the whole thing. There are two main things going on up there. And this is what it looks like:
/u/s/m/man3 > cat <<HERE
1 > line 1
2 > line 2
3 > line $((PS2c-1))
4 > HERE
line 1
line 2
line 3
/u/s/m/man3 >
PARSING $PWD
Every time $PS1
is evaluated it parses and prints $PWD
to add to the prompt. But I don't like the whole $PWD
crowding my screen, so I want just the first letter of every breadcrumb in the current path down to the current directory, which I'd like to see in full. Like this:
/h/mikeserv > cd /etc
/etc > cd /usr/share/man/man3
/u/s/m/man3 > cd /
/ > cd ~
/h/mikeserv >
There are a few steps here:
IFS=/
we're going to have to split the current $PWD
and the most reliable way to do that is with $IFS
split on /
. No need to bother with it at all afterward - all splitting from here on out will be defined by the shell's positional parameter $@
array in the next command like:
set -- ${PWD%"${last=${PWD##/*/}}"}
So this one's a little tricky, but the main thing is that we're splitting $PWD
on /
symbols. I also use parameter expansion to assign to $last
everything after any value occurring between the left-most and right-most /
slash. In this way I know that if I'm just at /
and have only one /
then $last
will still equal the whole $PWD
and $1
will be empty. This matters. I also strip $last
from the tail end of $PWD
before assigning it to $@
.
printf "${1+%c/}" "$@"
So here - as long as ${1+is set}
we printf
the first %c
haracter of each our shell's arguments - which we've just set to each directory in our current $PWD
- less the top directory - split on /
. So we're essentially just printing the first character of every directory in $PWD
but the top one. It's important though to realize this only happens if $1
gets set at all, which will not happen at root /
or at one removed from /
such as in /etc
.
printf "$last > "
$last
is the variable I just assigned to our top directory. So now this is our top directory. It prints whether or not the last statement did. And it takes a neat little >
for good measure.
BUT WHAT ABOUT THE INCREMENT?
And then there's the matter of the $PS2
conditional. I showed earlier how this can be done which you can still find below - this is fundamentally an issue of scope. But there's a little more to it unless you want to start doing a bunch of printf \b
ackspaces and then trying to balance out their character count... ugh. So I do this:
PS1='$(ps1)${PS2c##*[$((PS2c=0))-9]}'
Again, ${parameter##expansion}
saves the day. It's a little strange here though - we actually set the variable while we strip it of itself. We use its new value - set mid-strip - as the glob from which we strip. You see? We ##*
strip all from the head of our increment variable to the last character which can be anything from [$((PS2c=0))-9]
. We're guaranteed in this way not to output the value, and yet we still assign it. It's pretty cool - I've never done that before. But POSIX also guarantees us that this is the most portable way this can be done.
And it's thanks to POSIX-specified ${parameter} $((expansion))
that keeps these definitions in the current shell without requiring that we set them in a separate subshell, regardless of where we evaluate them. And this is why it works in dash
and sh
just as well as it does in bash
and zsh
. We use no shell/terminal dependent escapes and we let the variables test themselves. That's what makes portable code quick.
The rest is fairly simple - just increment our counter for every time $PS2
is evaluated until $PS1
once again resets it. Like this:
PS2='$((PS2c=PS2c+1)) > '
So now I can:
DASH DEMO
ENV=/tmp/prompt dash -i
/h/mikeserv > cd /etc
/etc > cd /usr/share/man/man3
/u/s/m/man3 > cat <<HERE
1 > line 1
2 > line 2
3 > line $((PS2c-1))
4 > HERE
line 1
line 2
line 3
/u/s/m/man3 > printf '\t%s\n' "$PS1" "$PS2" "$PS2c"
$(ps1)${PS2c##*[$((PS2c=0))-9]}
$((PS2c=PS2c+1)) >
0
/u/s/m/man3 > cd ~
/h/mikeserv >
SH DEMO
It works the same in bash
or sh
:
ENV=/tmp/prompt sh -i
/h/mikeserv > cat <<HEREDOC
1 > $( echo $PS2c )
2 > $( echo $PS1 )
3 > $( echo $PS2 )
4 > HEREDOC
4
$(ps1)${PS2c##*[$((PS2c=0))-9]}
$((PS2c=PS2c+1)) >
/h/mikeserv > echo $PS2c ; cd /
0
/ > cd /usr/share
/u/share > cd ~
/h/mikeserv > exit
As I said above, the primary problem is that you need to consider where you do your computation. You don't get the state in the parent shell - so you don't compute there. You get the state in the subshell - so that's where you compute. But you do the definition in the parent shell.
ENV=/dev/fd/3 sh -i 3<<\PROMPT
ps1() { printf '$((PS2c=0)) > ' ; }
ps2() { printf '$((PS2c=PS2c+1)) > ' ; }
PS1=$(ps1)
PS2=$(ps2)
PROMPT
0 > cat <<MULTI_LINE
1 > $(echo this will be line 1)
2 > $(echo and this line 2)
3 > $(echo here is line 3)
4 > MULTI_LINE
this will be line 1
and this line 2
here is line 3
0 >
Best Answer
x??
is expanded at the time of function call. So your function is already called withxaa xab xac
... .The simplest way would be to change the ordering of your parameters:
(look how I put
"
around every variable - this is to prevent bad things from happening if you have whitespace in your file names, what often happens with audio files)and call it with
makeaudiobook haskell x??
, i. e. with rotated arguments.