Ubuntu – Grep showing file name and string found

grep

I need an egrep command that list all the file names that contains the words + which string it has found. Let's imagine this scenario:

Words that I need to find: apple, watermelon and banana.

What I need: I want to list all files that contains any of them (don't need to have all of them in the same file), and print which word it found in the file. Example of a search result I want:

./file1.txt:apple
./file1.txt:banana
./file2.txt:watermelon
./file5.txt:apple

I remember seeing a grep command which shows FILENAME:STRING in the search results, but I can't remember how it was done. I tried:

egrep -lr 'apple|banana|watermelon' .

But the search results showed:

./file1.txt
./file2.txt

Ok, it helps but … in file1, which one of the words it found? That's the problem I'm facing .

Best Answer

You used -l, which is the opposite of what you want. From man grep:

-l, --files-with-matches
      Suppress normal output; instead print the  name  of  each  input
      file  from  which  output would normally have been printed.  The
      scanning will stop on the first  match.   (-l  is  specified  by
      POSIX.)

What you want is -H:

-H, --with-filename
      Print the file name for each match.  This is  the  default  when
      there is more than one file to search.

But that's the default anyway. Just do:

grep -Er 'apple|banana|watermelon' .

(The -E tells grep to act like egrep.)

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Ubuntu – Bash cut and grep commands through python

Suppose there is a file /home/eday/test.txt with the contents bellow:

this is a test


another line

CHECKOUT_REVISION this must be stored

some other things
CHECKOUT_REVISION another line to store

The following Python script will read the file stored in my_file variable looking for what is stored in look_for variable and if it finds a match, it will store it in temp variable which is a list variable.

Finally it will print to the output the contents of temp You can comment out or delete the printing line.

#!/usr/bin/env python

# path to the file to read from
my_file = "/home/eday/test.txt"
# what to look in each line
look_for = "CHECKOUT_REVISION"
# variable to store lines containing CHECKOUT_REVISION
temp = []

with open(my_file, "r") as file_to_read:
    for line in file_to_read:
        if look_for in line:
            temp.append(line)

# print the contents of temp variable
print (temp)

the above script will have the following output in terminal:

$ ['CHECKOUT_REVISION this must be stored', 'CHECKOUT_REVISION another line to store']

Ubuntu – grep — list file name where match is found

grep -H 75447A831E943724DD2DE9959E72EE31 *.html

-H, --with-filename
              Print the file name for each match. This is
              the default when there is more than one file
              to search.

Best Answer

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Ubuntu – Bash cut and grep commands through python

Ubuntu – grep — list file name where match is found

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