If you don't already have duplicates in the PATH and you only want to add directories if they are not already there, you can do it easily with the shell alone.
for x in /path/to/add …; do
case ":$PATH:" in
*":$x:"*) :;; # already there
*) PATH="$x:$PATH";;
esac
done
And here's a shell snippet that removes duplicates from $PATH. It goes through the entries one by one, and copies those that haven't been seen yet.
if [ -n "$PATH" ]; then
old_PATH=$PATH:; PATH=
while [ -n "$old_PATH" ]; do
x=${old_PATH%%:*} # the first remaining entry
case $PATH: in
*:"$x":*) ;; # already there
*) PATH=$PATH:$x;; # not there yet
esac
old_PATH=${old_PATH#*:}
done
PATH=${PATH#:}
unset old_PATH x
fi
You have the fields in the right order, but your first print statement adds a newline (Output Record Separator), so your data's there, but just wrapped unexpectedly.
The second issue is that you're telling printf to use a width of 4; that includes the decimal point and the two digits after it, leaving only one for the leading digit and none for any padding. Try using 5 as the width, so that your data is padded up to four total numbers. If you want 4 digits before the decimal point, then change the width to 7 instead.
This is the shortest change I made from your program to something that outputs what I think you want:
awk -F"|" '{
format = "%05.2f,%05.2f,%05.2f";
print $1","$2","$3","$4"," sprintf(format, $5,$6,$7)}' filename
I combined multiple { } blocks into one, and also combined the print statements into one.
If I was to write your awk statement from scratch, I might do something like this:
awk -v FS=\| -v OFS=, '{
$5=sprintf("%05.2f", $5);
$6=sprintf("%05.2f", $6);
$7=sprintf("%05.2f", $7);
print $1,$2,$3,$4,$5,$6,$7}' filename
It explicitly sets the input Field Separator, the Output Field Separator, explicitly converts each of the fields on its own, then prints the desired fields, with the OFS separating them.
Best Answer
how about this ?