Shell – Using curly brackets (braces) to create folder structure with `mkdir -p`

You can set a variable to hold the variant part. Like so:

domain='some-domain-1'
cd /domains/$domain/applications/j2ee-apps
domain='some-domain-2'
cd /domains/$domain/applications/j2ee-apps

Since the cd command is the same, you can recall it on your shell with the arrow keys.

Depending on how frequently you do this, you might want to define a function in your .bashrc.

cdj2(){
  cd /domains/"$1"/applications/j2ee-apps
}

Then you can cdj2 some-domain-1.

Shell globbing (aka pathname expansion) can take care of the other part (see Stéphane Gimenez's answer). The find command would be useful if the directory structures weren't exactly the same, but you still want to see all the files matching a certain name.

find /domains -name 'j2ee-apps' -exec ls {} \;

You could use a nested array loop, like this

#!/bin/bash
array_0=(one two three four five)
array_1=(x y z)

for a0 in "${array_0[@]}"
do
   for a1 in "${array_1[@]}"
   do
       mkdir -p "$HOME/web/$a0/$a1"
   done
done

Or, if you don't mind avoiding the use of arrays but using expansion lists instead, this single command will do much the same thing:

mkdir -p ~/{one,two,three,four,five}/{x,y,z}