Shell – Sorting Output of ‘find -print0’ with ‘sort’ Command

Yes, find ./work -print0 | xargs -0 rm will execute something like rm ./work/a "work/b c" .... You can check with echo, find ./work -print0 | xargs -0 echo rm will print the command that will be executed (except white space will be escaped appropriately, though the echo won't show that).

To get xargs to put the names in the middle, you need to add -I[string], where [string] is what you want to be replaced with the argument, in this case you'd use -I{}, e.g. <strings.txt xargs -I{} grep {} directory/*.

What you actually want to use is grep -F -f strings.txt:

-F, --fixed-strings
  Interpret PATTERN as a  list  of  fixed  strings,  separated  by
  newlines,  any  of  which is to be matched.  (-F is specified by
  POSIX.)
-f FILE, --file=FILE
  Obtain  patterns  from  FILE,  one  per  line.   The  empty file
  contains zero patterns, and therefore matches nothing.   (-f  is
  specified by POSIX.)

So grep -Ff strings.txt subdirectory/* will find all occurrences of any string in strings.txt as a literal, if you drop the -F option you can use regular expressions in the file. You could actually use grep -F "$(<strings.txt)" directory/* too. If you want to practice find, you can use the last two examples in the summary. If you want to do a recursive search instead of just the first level, you have a few options, also in the summary.

Summary:

# grep for each string individually.
<strings.txt xargs -I{} grep {} directory/*

# grep once for everything
grep -Ff strings.txt subdirectory/*
grep -F "$(<strings.txt)" directory/*

# Same, using file
find subdirectory -maxdepth 1 -type f -exec grep -Ff strings.txt {} +
find subdirectory -maxdepth 1 -type f -print0 | xargs -0 grep -Ff strings.txt

# Recursively
grep -rFf strings.txt subdirectory
find subdirectory -type f -exec grep -Ff strings.txt {} +
find subdirectory -type f -print0 | xargs -0 grep -Ff strings.txt

You may want to use the -l option to get just the name of each matching file if you don't need to see the actual line:

-l, --files-with-matches
  Suppress  normal  output;  instead  print the name of each input
  file from which output would normally have  been  printed.   The
  scanning  will  stop  on  the  first match.  (-l is specified by
  POSIX.)

Finding with ls: first things first, ls | grep cisco is a bit verbose, since cisco isn't a regular expression. Try:

ls *cisco*

Using find: along the same lines, -regex is overkill with a simple, static pattern. How about:

find -name '*cisco*'

The quotes are required so the glob is interpreted by find, not the shell. Also, -print is required for many versions of find, but is optional (and the default predicate) for others (e.g. GNU find). Feel free to add it if you need it.

If you need to search for ‘cisco’ in the full pathname, you could try this:

find -path '*cisco*'

which is equivalent to find | fgrep cisco.

Using find with regular expressions: let's do that anyway, since this is what you want. Shamelessly copying from the GNU find manpage:

-regex pattern

          File  name  matches  regular  expression  pattern.  This is a match
          on the whole path, not a search.  For example, to match a file named
          `./fubar3', you can use the regular expression `.*bar.' or `.*b.*3',
          but not `f.*r3'.

What this means is that your regular expression is wrapped in an invisible ^...$, so it must match every character in the full pathname of the file. So, as nwildner and otokan said in the comments, you should use something like:

find -regex '.*cisco.*'

And you don't even need the -regextype for something this simple.