I have a folder named 'sample' and it has 3 files in it. I want to write a shell script which will read these files inside the sample folder and post it to an HTTP site using curl.
I have written the following for listing files inside the folder:
for dir in sample/*; do
echo $dir;
done
But it gives me the following output:
sample/log
sample/clk
sample/demo
It is attaching the parent folder in it. I want the output as follows (without the parent folder name)
log
clk
demo
How do I do this?
Best Answer
Use
basename
to strip the leading path off of the files:Though why not: