Shell – How to get the positional parameters, starting from two, or more generally, `n`

arrayshellvariable

($@) Expands to the positional parameters, starting from one.

How can I get the positional parameters, starting from two, or more generally, n?

I want to use the positional parameters starting from two, as arguments to a command, for example,

myCommand $@

For positional parameters starting from the 5th one:

zsh or yash.
```
myCommand "${@[5,-1]}"
```
(note, as always, that the quotes above are important, or otherwise each element would be subject to split+glob in yash, or the empty elements removed in zsh).
ksh93, bash or zsh:
```
myCommand "${@:5}"
```
(again, quotes important)
Bourne-like shells (includes all of the above shells)
```
(shift 4; myCommand "$@")
```
(using a subshell so the shift only happens there).
csh-like shells:
```
(shift 4; myCommand $argv:q)
```
(subshell)
fish:
```
myCommand $argv[5..-1]
```
rc:
```
@{shift 4; myCommand $*}
```
(subshell)
rc/es:
```
myCommand $*(`{seq 5 $#*})
```
es:
```
myCommand $*(5 ...)
```

Use ${ } to enclosure a variable.

Without curly brackets:

VAR="foo"
echo $VAR
echo $VARbar

would give

foo

and nothing, because the variable $VARbar doesn't exist.

With curly brackets:

VAR="foo"
echo ${VAR}
echo ${VAR}bar

would give

foo
foobar

Enclosing the first $VAR is not necessary, but a good practice.

For your example:

#!/bin/sh
WEBSITE="danydiop" 
/usr/bin/mysqldump --opt -u root --ppassword ${WEBSITE} > ${WEBSITE}.sql

This works for bash, zsh, ksh, maybe others too.

You might also use an arithmetic for loop like this:

a=(user1 pass1 user2 pass2)
for ((i=0; i<${#a[@]}; i+=2)); do
  echo "${a[i]}: ${a[i+1]}"
done