Shell – How to find file/directory names that are the same, but with different capitalization/case

filenamesfindshell

How can I list the file/directory names in a directory recursively that are the same, but with different capitalization/case? ex.:

INPUT (not the ls command, the directories):

[user@localhost ~/a] ls -R
.:
b

./b:
ize  Ize

./b/ize:

./b/Ize:
[user@localhost ~/a]

OUTPUT:

/b/ize

Best Answer

If you have GNU uniq, you can sort case insensitively (-i), and use -d to print only duplicate lines:

find . | sort -f | uniq -di

As @StephaneChazelas mentioned in his answer, this might not do what you expect if you can have duplicate paths that only differ in case (like a/b/foo and A/b/foo).

Related Solutions

Bash – Find files with same name but different content

Update: fixed a typo in the script: changed print $NF to print $3; also tidied things up, and added some comments.

Assuming file names do not contain \n, the following prints out a sorted list which breaks (as in: section control breaks) at unique file name, unique md5sum, and shows the corresponding group of file paths.

#!/bin/bash

# Choose which script to use for the final awk step 
out_script=out_all

# Print all duplicated file names, even when md5sum is the same 
out_all='{ if( p1 != $1 ) { print nl $1; print I $2 }
      else if( p2 != $2 ) { print I $2 }
      print I I $3; p1=$1; p2=$2; nl="\n" }
   END { printf nl}'

# Print only duplicated file names which have multiple md5sums.
out_only='{ if( p1 != $1 ) { if( multi ) { print pend }
                             multi=0; pend=$1 "\n" I $2 "\n" }
       else if( p2 != $2 ) { multi++; pend=pend I $2 "\n" } 
       pend=pend I I $3 "\n"; p1=$1; p2=$2 } 
   END { if( multi ) print pend }'

# The main pipeline 
find "${1:-.}" -type f -name '*' |  # awk for duplicate names
awk -F/ '{ if( name[$NF] ) { dname[$NF]++ }
           name[$NF]=name[$NF] $0 "\n" } 
     END { for( d in dname ) { printf name[d] } 
   }' |                             # standard md5sum output 
xargs -d'\n' md5sum |               # " "==text, "*"==binary
sed 's/ [ *]/\x00/' |               # prefix with file name  
awk -F/ '{ print $3 "\x00" $0 }' |  # sort by name. md5sum, path 
sort |                              # awk to print result
awk -F"\x00" -v"I=   " "${!out_script}"

Output showing only file names with multiple md5s

afile.html
   53232474d80cf50b606069a821374a0a
      ./test/afile.html
      ./test/dir.svn/afile.html
   6b1b4b5b7aa12cdbcc72a16215990417
      ./test/dir.svn/dir.show/afile.html

Output showing all files with the same name.

afile.html
   53232474d80cf50b606069a821374a0a
      ./test/afile.html
      ./test/dir.svn/afile.html
   6b1b4b5b7aa12cdbcc72a16215990417
      ./test/dir.svn/dir.show/afile.html

fi    le.html
   53232474d80cf50b606069a821374a0a
      ./test/dir.svn/dir.show/fi    le.html
      ./test/dir.svn/dir.svn/fi    le.html

file.html
   53232474d80cf50b606069a821374a0a
      ./test/dir.show/dir.show/file.html
      ./test/dir.show/dir.svn/file.html

file.svn
   53232474d80cf50b606069a821374a0a
      ./test/dir.show/dir.show/file.svn
      ./test/dir.show/dir.svn/file.svn
      ./test/dir.svn/dir.show/file.svn
      ./test/dir.svn/dir.svn/file.svn

file.txt
   53232474d80cf50b606069a821374a0a
      ./test/dir.show/dir.show/file.txt
      ./test/dir.show/dir.svn/file.txt
      ./test/dir.svn/dir.show/file.txt
      ./test/dir.svn/dir.svn/file.txt

Get a list of directory names with find

With GNU find you can use the -printf option:

find . -maxdepth 1 -type d -printf '%f\n'

As noted by Paweł in the comments, if you don't want the current directory to be listed add -mindepth 1, e.g.:

find . -mindepth 1 -maxdepth 1 -type d -printf '%f\n'

Best Answer

Related Solutions

Bash – Find files with same name but different content

Get a list of directory names with find

Related Question