Nohup Command – How to Execute Multiple Commands Using Nohup

If you just want to write a single y to the stdin of the process, you can do this:

(echo y | nohup myprocess) &

If you want to keep writing y for every prompt that comes up, the coreutil yes exists for exactly this purpose -- it will keep writing whatever you tell it to to stdout. Its default is to output "y", so you can just:

(yes | nohup myprocess) &

but if you need something else you can pass it as an argument

For your command to detect eof, it has to read from stdin. So presumably it is expecting some input. So it sounds like what you need is not an empty input (/dev/null is exactly meant for that), but input that never comes.

It can be simulated with a pipe where nobody is ever going to write on the other end like:

sleep 999999999 | the-command

Or to avoid having to run that extra sleep command, it could be done with a named pipe:

fifo=$(mktemp -u) &&
  mkfifo "$fifo" &&
  (rm "$fifo" && the-command <&3 3<&- &) 3<> "$fifo"

Here using an intermediary file descriptor to work around the fact that the shell connects stdin to /dev/null implicitely when you start a command with & (unless you add an explicit stdin redirection like our <&3 here).

On Linux (and probably on Linux only), you can also do:

the-command < /dev/fd/1 3>&1 > /dev/null | :

/dev/fd/1 where fd 1 is connected to a pipe, on Linux, behaves like a named pipe. That is, when you open it in read mode, you get the reading end of the pipe.

So above, fd 0 will be connected to the reading end of a pipe whose other end is on the fd 3 of the-command. Because the-command is not going to write anything on its fd 3, any read attempt on fd 0 will block (or a non-blocking read will return with there's nothing to read yet, or a select/poll will return nothing to read either as the-command is probably doing if it's doing anything else than waiting for input that never comes).