I have used pipeline to read specific record from impala shell. Here is what I got
[cloudera@localhost ~]$ echo "select * from abc where key > 'a-26052014015400' limit 1;" | impala-shell
Starting Impala Shell without Kerberos authentication
Connected to localhost.localdomain:21000
Server version: impalad version cdh5-1.3.0 RELEASE (build 40e1b62cf0b97f666d084d9509bf9639c575068c)
Welcome to the Impala shell. Press TAB twice to see a list of available commands.
Copyright (c) 2012 Cloudera, Inc. All rights reserved.
(Shell build version: Impala Shell vcdh5-1.3.0 (40e1b62) built on Tue Mar 25 13:46:44 PDT 2014)
Query: select * from abc where key > 'a-26052014015400' limit 1
[localhost.localdomain:21000] > +------------------------+------+----------------+-------+
| key | hpid | uts | value |
+------------------------+------+----------------+-------+
| a-26052014015700 | HS2 | 26052014015450 | 50 |
+------------------------+------+----------------+-------+
Returned 1 row(s) in 2.42s
Goodbye
What I really want is a-26052014015700 | HS2 | 26052014015450 | 50 this record in awk programming. I have tried with pipelined awk command
`echo "select * from abc where key > 'a-26052014015400' limit 1;" | impala-shell| awk -F'=' '{print $2}' | awk -F '>' '{print $1}`
but didn't get the expected output. Any better and efficient method to extract the record?
Best Answer
try to pipe it to
grep:to get rid of the first
|and the last|:"-E" to access the extended regular expression syntax
"-o" is used to only output the matching segment of the line, rather than the full contents of the line.