Shell – get parts of string using shell script

shellshell-scriptstring

I have one string as

/ip/192.168.0.1/port/8080/

I want to get two separate variables which will contain port and IP

like. 192.168.0.1 and 8080

as I know /ip/ and /port/ will be there always I got Ip as follows,

expr /ip/192.168.0.1/port/8080/ : '/ip/\(.*\)/port/'

this will output 192.168.0.1
just don't know how to get port,
I tried similar command as,

expr /ip/192.168.0.1/port/8080/ : '/port/\(.*\)/'

but it doesn't give port .. how to get port also.

You can use awk:

awk -F\/ '{print $2"="$3, $4"="$5}' input_file

with either an input file or just line by line.

Try this:

newname=`echo "$filename" | sed -e 's/\(S[0-9][0-9]E[0-9][0-9]\).*\.mp4/\1.mp4/'`

The regular expression is:

In the replacement expression:

One more awk, just for fun:

$ a="aaa bbb aaa bbb ccc aaa ddd bbb ccc"
$ echo "$a" | awk '{for (i=1;i<=NF;i++) if (!a[$i]++) printf("%s%s",$i,FS)}{printf("\n")}'
aaa bbb ccc ddd

By the way, even your solution works fine with variables:

$ b="zebra ant spider spider ant zebra ant" 
$ echo "$b" | xargs -n1 | sort -u | xargs
ant spider zebra