Previously I used source command like this:
source file_name
But what I'm trying to do is this:
echo something | source
Which doesn't work.
Shell Pipe – How to Feed Source Command with a Pipe
pipeshell
pipeshell
Previously I used source command like this:
source file_name
But what I'm trying to do is this:
echo something | source
Which doesn't work.
Best Answer
Since
source(or.) takes a file as argument, you could try process substitution: