With awk:
awk -F'.' '{print $1}' file
-F option change default field separator(space) to dot(.).
$1 is index of field position(with . field separator).
{ILMN_1343291 TGTGTTGAGAGCTTCTCAGACTATCCACCTTTGGGTCGCTTTGCTGTTCG NM_001402}.{5}
^^ field index is $1 ^^$2
With rev and awk:
rev file | awk -F'.' '{print $2}'|rev # reverse characters of each lines,\
print field number 2 with (.) separator \
and reverse the result again
The rev utility copies the specified files to standard output, reversing the order of characters in every line. If no files are specified, standard input is read.
With sed:
sed 's/.[0-9]*$//' file
sed 's/.[^.]*$//' file
$ point to end of line. In first sed command search for char(.) which followed by zero or more occurrences of numbers and replace them with whitespace.
In second sed command remove everything that followed by (.) and also remove dot(.) itself.
With rev and sed:
rev file| sed 's/.*[.]//' |rev
Delete everything before dot(.) Also include and remove . itself.
With grep:
grep -oP '.*(?=\.[0-9])' file
-o, --only-matching
Print only the matched (non-empty) parts of a matching line,
with each such part on a separate output line.
-P, --perl-regexp
Interpret PATTERN as a Perl compatible regular expression (PCRE)
(?=pattern): Positive Lookahead: The positive lookahead construct is a pair of parentheses, with the opening parenthesis followed by a question mark and an equals sign.
.*(?=\.[0-9]): (positive lookahead) matches everything(.*) followed by one dot(.) and any occurrences of numbers, without making the pattern(\.[0-9]) part of the match.
With rev and grep:
rev file |grep -oP '(?<=[0-9]\.).*' |rev
rev file |grep -oP '[0-9]\.\K.*' |rev
(?<=pattern): Positive Lookbehind. A pair of parentheses, with the opening parenthesis followed by a question mark, "less than" symbol, and an equals sign.
(?<=[0-9]\.).* (positive lookbehind) matches everything which followed by any occurrences of numbers and end with dot(.).
In second grep command, you can use the nifty \K in place of the lookbehind assertion.
With cut:
cut -f1 -d. file
cut -c 1-77 file # Print first 77 characters of each line.
cut - remove sections from each line of files
-d, --delimiter=DELIM
use DELIM instead of TAB for field delimiter
-f, --fields=LIST
select only these fields;
-c, --characters=LIST
select only these characters
With while loop:
while read line; do echo "${line::-2}";done <file
This will work if you have only number with length=1 at the end of each lines and they are fix length. above command remove last two character at the end of every lines in input file. alternative commands is ${line%??}.
Best Answer
Another solution with
awkusingsub:Output:
Explanation:
-F,: set the comma as input field separatorOFS=,: set the comma as output filed separator (a space by default)sub("^[0-9]+\\s","",$3): erase numbers followed by a space at the beginning of the string$3and print the current line (because "print" is the default action inawk)In this way you can edit the desired column and print all the others (that in general may be many).