Linux – Is the BST time zone an hour behind

probably a bit late, but have you tried to setting ntp?

Although; use with caution, it may be some security concerns involving ntp, I'm just providing this. in hope it will be useful.

timedatectl set-ntp true

Network Time Protocol Security concerns -en.wikipedia.org

You could also try:

gsettings set org.gnome.desktop.datetime automatic-timezone true

Note: If something downright wrong with any of my posts is spotted; Please point that out right away! //thanks! Appreciate it!

I've had this problem quite a lot for the time being, and I have solved it (probably isn't the most optimal way) by:

timedatectl set-time <the actual **correct time**>

timedatectl set-timezone <Your timezone>

and, then - after that you try:

timedatectl set-ntp true

Hope this helps someone in the future.

The file system doesn't give you a time with timezone, it's whatever command that you use to display that time in a human friendly format that may give you a timezone if it chooses to display the time in local time (as specified by /etc/localtime, $TZ or other).

Generally, timestamps on Unix are expressed in a way that is irrelevant of timezones. The unix epoch time is the number of seconds (seconds expressed as the 86400th part of a day, so varying in length but more useful for calendar calculation) since a precise event in history (1970-01-01 00:00:00 UTC, an unambiguous time). Timezones only come into the picture when displaying a date in a calendar format to a human.

ps -o lstart= -p "$pid"
date -r /some/file

both give you the local time. date might output the timezone offset or not depending on the locale. If you want the UTC time, run them under TZ=UTC0:

TZ=UTC0 ps -o lstart= -p "$pid"
TZ-UTC0 date -r /some/file # or use date -u

GNU date is able to parse the date reported by ps, so you can convert it to any format, like the unix epoch time:

(export TZ=UTC0
date -d "$(ps -o lstart -p "$pid") +%s
date -r /some/file +%s)

(above using UTC time. It would also work with whatever the local time is in your environment except for one hour in the year where a time output without TZ indication is ambiguous (in zones that implement DST)).

In any case, the start time of a process doesn't have to be (and never is exactly) the time that process executed the command it is currently running. For instance:

$ TZ=UTC0 strace -qtt -e execve sh -c 'sleep 3; exec env ps -o lstart= -p "$$"'
10:27:24.877397 execve("/bin/sh", ["sh", "-c", "sleep 3; exec env ps -o lstart= "...], [/* 28 vars */]) = 0
10:27:27.882553 execve("/usr/bin/env", ["env", "ps", "-o", "lstart=", "-p", "9397"], [/* 28 vars */]) = 0
10:27:27.885272 execve("/bin/ps", ["ps", "-o", "lstart=", "-p", "9397"], [/* 28 vars */]) = 0
Fri May  5 10:27:24 2017

That 9397 process is running 4 commands in its life time: strace (forked there), sh, env, ps. The time reported by ps corresponds to the time when it was forked by strace, not when it executed ps.

If you want to get subsecond precision (up to 1/$(getconf CLK_TCK)), with zsh, you could do:

zmodload zsh/datetime
tick=$(getconf CLK_TCK)
(echo $((EPOCHREALTIME + (${${=$(</proc/self/stat)##*)}[20]}. -
          ${${=$(</proc/$pid/stat)##*)}[20]})/tick)))

That is we get the start time of the $pid and of a newly created subshell (that's the 20th fields after the last occurrence of a ) character in /proc/pid/stat expressed in CLK_TCK in modern versions of Linux), divide the difference by CLK_TCK and add to the current time.