Linux – Grep words with special symbols

greplinuxspecial characters

How do I grep this? (Including the special characters)

"Limit reached."[\n]"

I tried back-slashing the special symbols but end up not working, like this:

grep '\"Limit reached\.\"\[\\n\]\" '

I also tried other techniques but also not working. Is there any other syntax you could suggest/advice?

Best Answer

use -F in grep

$ cat test.txt
"Limit reached."[\n]"
test
"Limit reached."[\n]"

$ grep -F '"Limit reached."[\n]"' test.txt
"Limit reached."[\n]"
"Limit reached."[\n]"

As per Manual page,

   -F, --fixed-strings, --fixed-regexp
          Interpret PATTERN as a list of fixed strings, separated by newlines, any of which is to be matched.  (-F is specified by> POSIX,
 --fixed-regexp is an obsoleted alias, please do not use it new scripts.)

Related Solutions

How to grep for a value after an = sign

To include all other characters in your grep you could use this:

egrep -Eo '9701=.{1,50}' test.log

The dot represents ANY character.

But that won't cut off the "9701=" part of each line. To achieve this you could use cut

cut -d "=" -f 2- test.log

Though this would stumble if the value would include = as well.

sed would fix this for you and is ultimately the better solution for your problem:

sed -r 's/^9701=(.*)$/\1/' test.log

sed 's/^9701=\(.*\)$/\1/' test.log

or even

sed 's/^9701=//' test.log

Best Answer

Related Solutions

How to grep for a value after an = sign

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