Linux – Find and remove audio files which has less than 3 minutes of play duration

audiofindlinux

Is there a way to find and delete all the audio files recursively (MP3 files) which have less than 3 minutes play duration time?

Consider the situation that I have mixture of multiple format files (e.g. directories, text files and mp3 files).

Best Answer

Here's one way. Run mediainfo against every mp3 file, if shorter than 3 minutes, delete it.

#!/bin/bash
for FILE in $(find . -type f -name \*.mp3); do
    [[ $(mediainfo --Output='Audio;%Duration%' "${FILE}") -lt "180000" ]] && rm "${FILE}"
done

Or for fans of one-liners:

find . -type f -name \*.mp3 -exec bash -c '[[ $(mediainfo --Output="Audio;%Duration%" $1) -lt "180000" ]] && rm "$1"' -- {} \;

Related Solutions

Search MP3/Ogg files by tags/parameters from the command line

There are many FUSE-based "Media File Systems". tagsfs or pytagsfs might fit your needs, not sure if it's readily available, though (e.g. there's no official Debian package as far as I can see).

Be aware that traversing the resulting (virtual) file systems is not advisable; i.e. just ls your query, don't find.

Shell – Find, count and sort all audio files. ALAC (M4A) files

You should decompose your goal into several steps easier to solve. This will have two advantages:

It will be easier to solve,
The resulting code will be clearer and more reusable.

The scripts below basically follows these steps:

Generate raw statistic files. An easy way is to append the file size and the file name in a temporary file named after the original file extension. So, if you have the file /path/to/foo.mp3 which is 3000000 large, it will append 3000000 /path/to/foo.mp3 at the end of a temporary file named mp3.
Handle specific cases. Here it will process the temporary file m4a and create the two other files m4a_aac and m4a_alac based on the test you gave in the question.
Generate output. All the needed information being now available, it just has to:
- Count the number of line in each temporary file to determine the number of file of this type,
- Sum up each size to get the total size of files of this type.

Here is the script:

#!/bin/sh

# This script takes the searched directory as first parameter.
# For instance: ./this-script.sh ~/Music

: ${1:?"You must pass the search directory as first parameter."}
searchdir="$1"

# Create a temporary directory
statsdir=""
trap 'rm -rf $statsdir' EXIT
statsdir=$(mktemp -d "/tmp/tmp.XXXXXXXXXX") || exit 1

# Generate one listing file per extension
awkscript='/\.[[:alnum:]]+$/ {print $0 >statsdir"/"$(NF)}'
# For Linux: stat -c "%s %n"
# For Mac: stat -f "%z %N"
find "$searchdir" -type f -exec stat -f "%z %N" {} + | \
    awk -F '.' -v statsdir="$statsdir" "$awkscript"

# Distinguish between m4a/AAC and m4a/ALAC
if [ -f "$statsdir/m4a" ]; then
    input="$statsdir/m4a"
    while IFS= read -r line; do
        filename=${line#* }
        if avprobe "$filename" 2>&1 | grep -q 'Audio: alac'; then
            echo "$line" >> "$statsdir/m4a_alac"
        else
            echo "$line" >> "$statsdir/m4a_aac"
        fi
    done < "$input"
    rm "$statsdir/m4a"
fi

# Generate and display result
{
    printf "Type Count Size\n"
    for extension in $(ls "$statsdir"); do
        count=$(wc -l "$statsdir/$extension" | cut -d ' ' -f 1)
        totalsize=$(awk '{s+=$1} END {print s}' "$statsdir/$extension")
        printf "%s %d %d\n" "$extension" "$count" "$totalsize"
    done
} | column -t

Best Answer

Related Solutions

Search MP3/Ogg files by tags/parameters from the command line

Shell – Find, count and sort all audio files. ALAC (M4A) files

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