How to Replace Path in Search field using VIM

regular expressionvim

I'm trying to replace this text in VIM

Actual Path /home/omipenguin/Servers\ Information/systemscript.sh/sysinfo.txt

with this new path

/home/sysinfo

I tried

%s/\/home\/omipenguin\/Servers\ Information\/systemscript.sh\/sysinfo.txt//home/sysinfo/g

but VIM gives me Pattern not Found. What is wrong?

Best Answer

The forward slash / is used by vim as the default pattern separator: it separates the pattern from the substitution you want to make, so vim misconstrued the slashes in your path. You can specify another separator, like so:

%s!/home/omipenguin/Servers\\ Information/systemscript.sh/sysinfo.txt!/home/sysinfo!g

Note how you also need to escape the backslash \ because of its special meaning in regular expressions.

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Vim: use string from search in replace command

In general, an empty regular expression means to use the previously entered regular expression, so :%s//\1/g should do what you want.

Replace using VIM, reuse part of the search pattern

\0 is the whole match. To use only part of it you need to set it like this and use \1

.s/(\([0-9]*\))/{\1}/

More detailed instruction you can find here or in vim help.

Best Answer

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Vim: use string from search in replace command

Replace using VIM, reuse part of the search pattern

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