The following command line uses awk to prepend the last field of each line of file.txt, does a reverse numerical sort, then uses cut to remove the added field:
awk '{print $NF,$0}' file.txt | sort -nr | cut -f2- -d' '
Almost there. Just put both column references next to each other.
cat logfile | sed 's/|/ /' | awk '{print $1, $8}'
Also note that you don't need cat here.
sed 's/|/ /' logfile | awk '{print $1, $8}'
Also note you can tell awk that the column separators is |, instead of blanks, so you don't need sed either.
awk -F '|' '{print $1, $8}' logfile
As per suggestions by Caleb, if you want a solution that still outputs the last field, even if there are not exactly eight, you can use $NF.
awk -F '|' '{print $1, $NF}' logfile
Also, if you want the output to retain the | separators, instead of using a space, you can specify the output field separators. Unfortunately, it's a bit more clumsy than just using the -F flag, but here are three approaches.
You can assign the input and output field separators in awk itself, in the BEGIN block.
awk 'BEGIN {FS = OFS = "|"} {print $1, $8}' logfile
You can assign these variables when calling awk from the command line, via the -v flag.
awk -v 'FS=|' -v 'OFS=|' '{print $1, $8}' logfile
or simply:
awk -F '|' '{print $1 "|" $8}' logfile
Best Answer
It can even be done only with
'bash', without'sed','awk'or'perl':