Say I have folder "foo" residing, the home directory. I want to get some info of it, owner, group, permissions, etc…
I then do this to try to get the information:
cd ~
ls -l foo
Of course it now lists the info of the contents of "foo"
Then I could do something like this
cd ~
dir=foo
ls -l $foo/.. | awk 'BEGIN { dir="'$foo'" } { if($9 == dir) { print $0 } }'
But isn't there an easier way to do this?
Best Answer
Try
And you will get what you want.
But also consider
stat
if you want to capture information. The output ofls
is for human consumption only.