I have a file as the following
200.000 1.353 0.086
200.250 1.417 0.000
200.500 1.359 0.091
200.750 1.423 0.000
201.000 1.365 0.093
201.250 1.427 0.000
201.500 1.373 0.093
201.750 1.432 0.000
202.000 1.383 0.091
202.250 1.435 0.000
202.500 1.392 0.087
202.750 1.436 0.000
203.000 1.402 0.081
203.250 1.437 0.001
203.500 1.412 0.073
204.000 1.423 0.065
204.500 1.432 0.055
205.000 1.441 0.045
I would like to grep only the rows that have in the first column the decimal .000 and .500 only so the output would be like this
200.000 1.353 0.086
200.500 1.359 0.091
201.000 1.365 0.093
201.500 1.373 0.093
202.000 1.383 0.091
202.500 1.392 0.087
203.000 1.402 0.081
203.500 1.412 0.073
204.000 1.423 0.065
204.500 1.432 0.055
205.000 1.441 0.045
Best Answer
You don't use grep. Use
awk
.