You can always do:
tac < fileName | sed '/EndPattern/,$!d;/StartPattern/q' | tac
If your system doesn't have GNU tac, you may be able to use tail -r instead.
You can also do it like:
awk '
inside {
text = text $0 RS
if (/EndPattern/) inside=0
next
}
/StartPattern/ {
inside = 1
text = $0 RS
}
END {printf "%s", text}' < filename
But that means reading the whole file.
Note that it may give different results if there's another StartPattern in between a StartPattern and the next EndPattern or if the last StartPattern does not have an ending EndPattern or if there are lines matching both StartPattern and EndPattern.
awk '
/StartPattern/ {
inside = 1
text = ""
}
inside {text = text $0 RS}
/EndPattern/ {inside = 0}
END {printf "%s", text}' < filename
Would make it behave more like the tac+sed+tac approach (except for the unclosed trailing StartPattern case).
That last one seems to be the closest to your edited requirements. To add the warning would simply be:
awk '
/StartPattern/ {
inside = 1
text = ""
}
inside {text = text $0 RS}
/EndPattern/ {inside = 0}
END {
printf "%s", text
if (inside)
print "Warning: EOF reached without seeing the end pattern" > "/dev/stderr"
}' < filename
To avoid reading the whole file:
tac < filename | awk '
/StartPattern/ {
printf "%s", $0 RS text
if (!inside)
print "Warning: EOF reached without seeing the end pattern" > "/dev/stderr"
exit
}
/EndPattern/ {inside = 1; text = ""}
{text = $0 RS text}'
Portability note: for /dev/stderr, you need either a system with such a special file (beware that on Linux if stderr is open on a seekable file that will write the text at the beginning of the file instead of the current position within the file) or an awk implementation that emulates it like gawk, mawk or busybox awk (those work around the Linux issue mentioned above).
On other systems, you can replace print ... > "/dev/stderr" with print ... | "cat>&2".
awk works well for this too: using [ or ] as the field separator, print every even-numbered field:
awk -F '[][]' '{for (i=2; i<=NF; i+=2) {printf "%s ", $i}; print ""}' file
With sed, I'd write
sed -E 's/(^|\])[^[]*($|\[)/ /g' file
Best Answer
The sed pattern matching
/first/,/second/reads lines one by one. When some line matches to/first/it remembers it and looks forward for the first match for the/second/pattern. In the same time it applies all activities specified for that pattern. After that process starts again and again up to the end of file.That's not that we need. We need to look up to the last matching of
/second/pattern. Therefore we build construction that looks just for the first entry/foo/. When found the cycleastarts. We add new line to the match buffer withNand check if it matches to the pattern/bar/. If it does, we just print it and clear the match buffer and janyway jump to the begin of cycle withba.Also we need to delete newline symbol after buffer clean up with
/^\n/s/^\n//. I'm sure there is much better solution, unfortunately it didn't come to my mind.Hope everything is clear.