BusyBox – How to Get 3 Minutes Future Date

busyboxdate

I want to get the date 3 minutes on the future. For example, if "now" is

01-Jan-70 00:00:00 GMT

I want to get

01-Jan-80 00:03:00 GMT

How should I do it? I'm working with busybox linux.

Best Answer

With GNU date you can do it as simple as this:

date --date="3min"

But busybox seems not so smart (yet). The only reliable solution I came up with using bb is:

busybox date -D '%s' -d "$(( `busybox date +%s`+3*60 ))"

(you don't need the busybox parts if there is no other date implementation present)

If you want a formatted output, you could add this

busybox date -D '%s' +"%y%m%d%H%" -d "$(( `busybox date +%s`+3*60 ))"

Related Solutions

How many minutes have passed since the Unix Epoch

#!/bin/bash

# Minutes since Epoch until now:
((minutes=$(date +%s)/60))

# Minutes since Epoch until Jan 1 2011:
((minutes=$(date -d 'Jan 1 2011' +%s)/60))

Linux – How to get relative date based on relative date by linux date command

If you have faketime and your date is dynamically linked:

faketime -f -10m date -d 'last monday' '+%F %T'

With ksh93 (only builtin commands):

printf '%(%F %T)T\n' "$(printf '%(%Y.%m.%d)T' '10 minutes ago')-0 last monday"

Here, if it was last Sunday instead of last Monday, you could do:

date -d "$(date -d '10 minutes ago' +"%F -%u day")"

Or if it was last Saturday:

date -d "$(date -d '10 minutes ago' +"%F -%w day -1 day")"

But for last Monday or any other day of the week, it involves a bit of arithmetic:

eval "date -d \"$(date -d '10 minutes ago' +'%F -$(((%u+5)%%7+1)) day')\""

Otherwise, you can always do:

d=$(date -d 'last monday'); sleep 600; printf '%s\n' "$d"

;-)

Best Answer

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How many minutes have passed since the Unix Epoch

Linux – How to get relative date based on relative date by linux date command

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