Directory Zip – How to Force Unzip/Zip Not to Create a Subdirectory

directoryzip

Depending on how a zip file is created, sometimes it will extract all of the files directly, and sometimes it will extract the files into a subdirectory.

If the latter is true, how can I force the unzip command to "ignore" that first level directory?

Example:

cd /tmp
wget http://omeka.org/files/omeka-1.5.1.zip
mkdir omeka
unzip omeka-1.5.1.zip -d omeka/
cd omeka/
ll

What I'm getting is /tmp/omeka/omeka-1.5.1/:

total 12
drwxr-xr-x 3 root root 4096 2012-05-08 18:44 ./
drwxrwxrwt 6 root root 4096 2012-05-08 18:44 ../
drwxr-xr-x 5 root root 4096 2012-04-20 14:54 omeka-1.5.1/

What I want is of the files extracted to /tmp/omeka/, (one level up and no version number included in the directory structure)

/tmp/omeka/(files)

I know I can use the -j option to "junk paths" but I want to keep the subdirectory structure, just not the top level directory structure. How can I do this?

Best Answer

Use a FUSE filesystem that allows you to browse archives like directories, such as AVFS. Use cp to extract the files to the directory of your choice.

mountavfs
cp -Rp ~/.avfs/tmp/omeka-1.5.1.zip\#/omeka-1.5.1 omeka

Since we're assuming that there is a single toplevel directory in the archive, you can shorten this to

cp -Rp ~/.avfs/tmp/omeka-1.5.1.zip\#/* omeka

Use Python's zipfile library?

~/wrk/tmp$ ls test.zip
ls: cannot access test.zip: No such file or directory

Ok. There is no 'test.zip' right now...

~/wrk/tmp$ python -c 'import zipfile,sys ; zipfile.ZipFile(sys.argv[1],"a").write(sys.a
rgv[2],sys.argv[3])' test.zip /etc/motd text/motd

Let's add '/etc/motd' as 'text/motd' to the nonexisting zipfile...

~/wrk/tmp$ ls -l test.zip 
-rw-r--r-- 1 yeti yeti 473 Mar 23 09:51 test.zip

The zipfile library was nice enough to create 'test.zip'.

~/wrk/tmp$ unzip -lv test.zip 
Archive:  test.zip
 Length   Method    Size  Cmpr    Date    Time   CRC-32   Name
--------  ------  ------- ---- ---------- ----- --------  ----
     357  Stored      357   0% 2014-03-20 15:47 ff1b8b7f  text/motd
--------          -------  ---                            -------
     357              357   0%                            1 file

..and it seems to contain what I wated...

Let's check it by unzipping it to stdout...

~/wrk/tmp$ unzip -p test.zip text/motd
Linux aurora 3.2.0-0.bpo.4-amd64 #1 SMP Debian 3.2.54-2~bpo60+1 x86_64

The programs included with the Debian GNU/Linux system are free software;
the exact distribution terms for each program are described in the
individual files in /usr/share/doc/*/copyright.

Debian GNU/Linux comes with ABSOLUTELY NO WARRANTY, to the extent
permitted by applicable law.

Fine!

Now we add a 2nd file...

~/wrk/tmp$ python -c 'import zipfile,sys ; zipfile.ZipFile(sys.argv[1],"a").write(sys.argv[2],sys.argv[3])' test.zip /etc/issue otherdir/issue
~/wrk/tmp$ ls -l test.zip 
-rw-r--r-- 1 yeti yeti 605 Mar 23 09:52 test.zip
(yeti@aurora:1)~/wrk/tmp$ unzip -lv test.zip 
Archive:  test.zip
 Length   Method    Size  Cmpr    Date    Time   CRC-32   Name
--------  ------  ------- ---- ---------- ----- --------  ----
     357  Stored      357   0% 2014-03-20 15:47 ff1b8b7f  text/motd
      28  Stored       28   0% 2012-09-21 22:52 f9c3990c  otherdir/issue
--------          -------  ---                            -------
     385              385   0%                            2 files
~/wrk/tmp$ unzip -p test.zip otherdir/issue                                            Debian GNU/Linux 6.0 \n \l

~/wrk/tmp$ _

Is it possible to fake destination directory path with zip

I don't see a way to do this using the zip command, but it's easy in python.

Note that the zip file format specification, section 4.4.17.1, says that the pathname cannot start with a '/', so I can't help with that part.

The python zipfile module will let you override a file's pathname when you add it to the zip archive; just pass the desired name as the optional 2nd argument to ZipFile.write:

ZipFile.write(filename[, arcname[, compress_type]])
Write the file named filename to the archive, giving it the archive name arcname (by default, this will be the same as filename, but without a drive letter and with leading path separators removed). If given, compress_type overrides the value given for the compression parameter to the constructor for the new entry.
Note: Archive names should be relative to the archive root, that is, they should not start with a path separator.

Here's an example:

$ touch 1 2 3
$ python
Python 2.7.6 (default, Mar 22 2014, 22:59:56) 
>>> import zipfile
>>> with zipfile.ZipFile('bundle.zip', 'w') as bundle:
...   bundle.write('1', '/bin/1')
...   bundle.write('2', '/sbin/2')
...   bundle.write('3', '/usr/bin/3')
... 
>>> 
$ unzip -l bundle
Archive:  bundle.zip
  Length      Date    Time    Name
---------  ---------- -----   ----
        0  2014-08-11 13:00   bin/1
        0  2014-08-11 13:00   sbin/2
        0  2014-08-11 13:00   usr/bin/3
---------                     -------
        0                     3 files

Note that zipfile.write will remove any leading '/' from the pathname, to conform with the standard.

Best Answer

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Use Python's zipfile library?

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