How to compare two dates without using Stat

awkdate

I'm trying to compare the last date modified of a file to today's date. If the modification date is before today's date then my script will do one thing, if the date matches todays date i need it to do another. Right now my code looks like this:

date2= ls -l file | awk '{print $6 $7}'
date1= date +%b%d

if (( $(printf "%(%s)T" "$date1") > $(printf "%(%s)T" "$date2") ))
then
  echo "date1 is after date2"
else
  echo "date1 is not after date2"
fi

This code is not working. Does anyone have any suggestions?

Best Answer

If you have GNU find installed, the following line will return the filename if it was last modified earlier than today

find yourfile -prune -daystart -mtime +0 -print

Related Solutions

Awk – Print Problem Solutions

Aside from functions, awk code looks like

condition {actions}

If the {actions} block is missing, the implicit action if the condition returns true is {print}.

If the condition is missing, and this directly relates to your question, it is implicitly true for every line of the input. That's why you get that line printed so many times.

You need to specify a condition. Either put the print statement inside the BEGIN block as Stéphane suggests, or you can do this:

NR == 1 {print "this is the header"}

That action only occurs when the condition is true, which is for the first line of input.

Linux – How to Compare Column1 of Two Files

#!/bin/bash

var=$(cut -d" " -f 1 file1)
var1=$(cut -d" " -f 1 file2)

if [ "$var" == "$var1" ]
then
echo "columns are matching each other "
else
echo "columns are not matching with each other!"

fi

Best Answer

Related Solutions

Awk – Print Problem Solutions

Linux – How to Compare Column1 of Two Files

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