How to compare the strings using < (Greater than symbol)

awksed

Below is my input file:

PA43410-2,1,3,/vobs/atlas-idc/src/utils/logger/IDCLogger/IDC.cpp,48,19:16:46.523.177, 2 PS Sensor Value = -5.501000 , Min = -5.583000 , Max = -5.319000
PA43410-2,1,3,/vobs/atlas-idc/src/utils/logger/IDCLogger/IDC.cpp,48,19:16:46.523.210, 3 PS Sensor Value = 15.996000 , Min = 15.814000 , Max = 16.078000
PA43410-2,1,3,/vobs/atlas-idc/src/utils/logger/IDCLogger/IDC.cpp,48,19:16:46.523.231, 4 PS Sensor Value = -16.505000 , Min = -16.587000 , Max = -16.323000
PA43410-2,1,3,/vobs/atlas-idc/src/utils/logger/IDCLogger/IDC.cpp,48,19:16:46.523.263, 5 PS Sensor Value = 6.509000 , Min = 6.327000 , Max = 6.591000
PA43410-2,1,3,/vobs/atlas-idc/src/utils/logger/IDCLogger/IDC.cpp,48,19:16:46.523.302, 6 PS Sensor Value = 4.002000 , Min = 3.820000 , Max = 4.084000
PA43410-2,1,3,/vobs/atlas-idc/src/utils/logger/IDCLogger/IDC.cpp,48,19:17:46.481.557, 1 PS Sensor Value = 6.199000 , Min = 6.017000 , Max = 6.281000
PA43410-2,1,3,/vobs/atlas-idc/src/utils/logger/IDCLogger/IDC.cpp,48,19:17:46.518.691, 2 PS Sensor Value = -5.503000 , Min = -5.585000 , Max = -5.321000
PA43410-2,1,3,/vobs/atlas-idc/src/utils/logger/IDCLogger/IDC.cpp,48,19:17:46.523.156, 3 PS Sensor Value = 15.996000 , Min = 15.814000 , Max = 16.078000
PA43410-2,1,3,/vobs/atlas-idc/src/utils/logger/IDCLogger/IDC.cpp,48,19:17:46.523.195, 4 PS Sensor Value = -16.505000 , Min = -16.587000 , Max = -16.323000
PA43410-2,1,3,/vobs/atlas-idc/src/utils/logger/IDCLogger/IDC.cpp,48,19:17:46.523.221, 5 PS Sensor Value = 6.509000 , Min = 6.327000 , Max = 6.591000
PA43410-2,1,3,/vobs/atlas-idc/src/utils/logger/IDCLogger/IDC.cpp,48,19:17:46.523.240, 6 PS Sensor Value = 4.002000 , Min = 3.820000 , Max = 4.084000
PA43410-2,1,3,/vobs/atlas-idc/src/utils/logger/IDCLogger/IDC.cpp,48,19:18:46.480.644, 1 PS Sensor Value = 6.199000 , Min = 6.017000 , Max = 6.281000
PA43410-2,1,3,/vobs/atlas-idc/src/utils/logger/IDCLogger/IDC.cpp,48,19:18:46.522.615, 2 PS Sensor Value = -5.501000 , Min = -5.583000 , Max = -5.319000
PA43410-2,1,3,/vobs/atlas-idc/src/utils/logger/IDCLogger/IDC.cpp,48,19:18:46.522.729, 3 PS Sensor Value = 15.996000 , Min = 15.814000 , Max = 16.078000
PA43410-2,1,3,/vobs/atlas-idc/src/utils/logger/IDCLogger/IDC.cpp,48,19:18:46.522.765, 4 PS Sensor Value = -16.505000 , Min = -16.587000 , Max = -16.323000
PA43410-2,1,3,/vobs/atlas-idc/src/utils/logger/IDCLogger/IDC.cpp,48,19:18:46.522.788, 5 PS Sensor Value = 6.509000 , Min = 6.327000 , Max = 6.591000
PA43410-2,1,3,/vobs/atlas-idc/src/utils/logger/IDCLogger/IDC.cpp,48,19:18:46.522.810, 6 PS Sensor Value = 4.002000 , Min = 3.820000 , Max = 4.084000

I need to compare the PS Sensor Value, Min and Max value. (Min greater than PS Sensor greater than Max)

I'm expecting the output like below and here I should have only the normal lines.

What is normal lines? :
If Min value greater than PS Sensor value && PS Sensor value is greater than Max value then the line is normal lines and that should removed.

Expected Output:
PA43410-2 PS Sensor Value = 6.509000 , Min = 6.327000 , Max = 6.591000
PA43410-2 PS Sensor Value = 6.199000 , Min = 6.017000 , Max = 6.281000

Eg:

   If   Min < PS sensor value < Max,    // Don’t care the normal  lines.
         Throw this line away.
   Else  
        Pull this line to consolidated new file. //Only focus on abnormal lines.

Best Answer

A simple solution is to use awk. Since awk splits its input into fields on whitespace (by default), the PS sensor value will be field 7 ($7), the min will be $11 and the max will be $15. You can, therefore, do:

awk  '$7>$11 && $7<$15' file > new.file

The default action when an expression evaluates to true in awk is to print the current line. Therefore, the command above will print all lines whose 7th field is between the min and max values.

Related Solutions

Perl or awk solution for this problem

Here is awk solution:

$ awk '
    $4 < 1.5 {
      uniq[$1] = $3;
      uniq[$2] = $3;
      next;
  }
  {
      uniq[$1] = $3;
      dup[$2] = $3;
      delete uniq[$2];
  }
  END {
    print "--unique.txt--";
    for(i in uniq) {
        print i,uniq[i]
    }
    print "";
    print "--duplicate.txt--";
    for(i in dup) {
        print i,dup[i]
    }
    }' file
--unique.txt--
764157 ericcartman
56797854 ericcartman
53723848 timburnes

--duplicate.txt--
53530214 timburnes
52986038 ericcartman
12651711 timburnes

With your second example:

$ awk '
    $4 < 1.5 {
      uniq[$1] = $3;
      uniq[$2] = $3;
      next;
  }
  {
      uniq[$1] = $3;
      dup[$2] = $3;
      delete uniq[$2];
  }
  END {
    print "--unique.txt--";
    for(i in uniq) {
        print i,uniq[i]
    }
    print "";
    print "--duplicate.txt--";
    for(i in dup) {
        print i,dup[i]
    }
    }' << END
> 17412193 43979400 ericcartman 2.16667
> 21757330 54678379 andrewruss 0.55264
END
--unique.txt--
21757330 andrewruss
54678379 andrewruss
17412193 ericcartman

--duplicate.txt--
43979400 ericcartman

Counting the number of lines having a number greater than 100

Let's consider this test file:

$ cat myfile
98
99
100
101
102
103
104
105

Now, let's count the number of lines with a number greater than 100:

$ awk '$1>100{c++} END{print c+0}' myfile
5

How it works

$1>100{c++}

Every time that the number on the line is greater than 100, the variable c is incremented by 1.
END{print c+0}

After we have finished reading the file, the variable c is printed.

By adding 0 to c, we force awk to treat c like a number. If there were any lines with numbers >100, then c is already a number. If there were not, then c would be an empty (hat tip: iruvar). By adding zero to it, we change the empty string to a 0, giving a more correct output.

Best Answer

Related Solutions

Perl or awk solution for this problem

Counting the number of lines having a number greater than 100

How it works

Related Question