Command Line – Get Files Modified on a Specific Date

What is happening here is that when you use the -R option to cp and supply a directory as an argument, it copies everything in that directory. Moreover, this will not preserve the directory structure as any files in lower directories will be copied directly to /tmp/2. This may be what you want (see X Tian's answer for how to do it this way), but beware if any files have the same name, one will overwrite the other at the detination.

To preserve the directory structure, you can use cpio:

find . -mtime -60 -print0 | cpio -0mdp /tmp/2

If the -0 (or equivalent) option is unavailable, you can do this, but be careful none of your file names contains a newline:

find . -mtime -2 | cpio -mdp /tmp/2

cpio should also support the -L option, although be careful with this as in some cases it can cause an infinite loop.

Assuming you have your desired files in a text file, you could do something like

while IFS= read -r file; do 
    echo mkdir -p ${file%/*}; 
    cp /source/"$file" /target/${file%/*}/${file##*/}; 
done < files.txt 

That will read each line of your list, extract the directory and the file name, create the directory and copy the file. You will need to change source and target to the actual parent directories you are using. For example, to copy /foo/a/a.txt to /bar/a/a.txt, change source to foo and target to bar.

I can't tell from your question whether you want to copy all directories and then only specific files or if you just want the directories that will contain files. The solution above will only create the necessary directories. If you want to create all of them, use

find /source -type d -exec mkdir -p {} /target

That will create the directories. Once those are there, just copy the files:

while IFS= read -r file; do 
    cp /source/"$file" /target/"$file"
done

Update

This little script will move all the files modified after September 8. It assumes the GNU versions of find and touch. Assuming you're using Linux, that's what you will have.

#!/usr/bin/env bash    

## Create a file to compare against.
tmp=$(mktemp)
touch -d "September 8" "$tmp"

## Define the source and target parent directories
source=/path/to/source
target=/path/to/target

## move to the source directory
cd "$source"

## Find the files that were modified more recently than $tmp and copy them
find ./ -type f -newer "$tmp" -printf "%h %p\0" | 
    while IFS= read -rd '' path file; do
        mkdir -p "$target"/"$path"
        cp "$file" "$target"/"$path"
    done

Strictly speaking, you don't need the tmp file. However, this way, the same script will work tomorrow. Otherwise, if you use find's -mtime, you would have to calculate the right date every day.

Another approach would be to first find the directories, create them in the target and then copy the files:

1. Create all directories

    find ./ -type d -exec mkdir -p ../bar/{} \;
   

2. Find and copy the relevant files

    find ./ -type f -newer "$tmp" -exec cp {} /path/to/target/bar/{} \;
   

3. Remove any empty directories

    find ../bar/ -type d -exec rmdir {} \;