Get a list of directory names with find

directoryfind

I know I can do this to get a list of directory names:

find . -type d -maxdepth 1

The output looks like this:

.
./foo
./bar

I prefer the listing without ./. Is there a way to get find to output just the raw names?

I tried sending the list to stat to format it but that just gives me the same result:

find . -type d -maxdepth 1 -print0 | xargs -0 stat -f '%N'

Best Answer

With GNU find you can use the -printf option:

find . -maxdepth 1 -type d -printf '%f\n'

As noted by Paweł in the comments, if you don't want the current directory to be listed add -mindepth 1, e.g.:

find . -mindepth 1 -maxdepth 1 -type d -printf '%f\n'

Related Solutions

Exclude directory in find

find . -name 'foo-exclude-me' -prune -o -name 'foo*' -print

With no -print, the implicit default action applies to every match, even pruned ones. The explicit -print applies only under the specified conditions, which are -name 'foo*' only in the else branch of -name 'foo-exclude-me'.

Generally speaking, use an explicit -print whenever you're doing something more complex than a conjunction of predicates.

Your second attempt with ! -path './foo-exclude-me/*' didn't work because ./foo-exclude-me doesn't match ./foo-exclude-me/* (no trailing /). Adding ! -path ./foo-exclude-me would work.

“find” output relative to directory

If what you are trying to do is not too complex, you could accomplish this with sed:

find diskimg | sed -n 's|^diskimg/||p'

Or cut:

find diskimg | cut -sd / -f 2-

Best Answer

Related Solutions

Exclude directory in find

“find” output relative to directory

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