Find & Delete directories in .zip files

(Adapted from How do I recursively grep through compressed archives?)

Install AVFS, a filesystem that provides transparent access inside archives. First run this command once to set up a view of your machine's filesystem in which you can access archives as if they were directories:

mountavfs

After this, if /path/to/archive.zip is a recognized archive, then ~/.avfs/path/to/archive.zip# is a directory that appears to contain the contents of the archive.

find ~/.avfs"$PWD" \( -name '*.7z' -o -name '*.zip' -o -name '*.tar.gz' -o -name '*.tgz' \) \
     -exec sh -c '
                  find "$0#" -name "*vacation*.jpg"
                 ' {} 'Test::Version' \;

Explanations:

• Mount the AVFS filesystem.
• Look for archive files in ~/.avfs$PWD, which is the AVFS view of the current directory.
• For each archive, execute the specified shell snippet (with $0 = archive name and $1 = pattern to search).
• $0# is the directory view of the archive $0.
• {\} rather than {} is needed in case the outer find substitutes {} inside -exec ; arguments (some do it, some don't).

Or in zsh ≥4.3:

mountavfs
ls -l ~/.avfs$PWD/**/*.(7z|tgz|tar.gz|zip)(e\''
     reply=($REPLY\#/**/*vacation*.jpg(.N))
'\')

Explanations:

• ~/.avfs$PWD/**/*.(7z|tgz|tar.gz|zip) matches archives in the AVFS view of the current directory and its subdirectories.
• PATTERN(e\''CODE'\') applies CODE to each match of PATTERN. The name of the matched file is in $REPLY. Setting the reply array turns the match into a list of names.
• $REPLY\# is the directory view of the archive.
• $REPLY\#/**/*vacation*.jpg matches *vacation*.jpg files in the archive.
• The N glob qualifier makes the pattern expand to an empty list if there is no match.

I think something went wrong with the creation of the zip file, because when I create a zip file on Windows is has (portable) forward slashes:

zip.exe -r pip pip
updating: pip/ (244 bytes security) (stored 0%)
  adding: pip/pip.log (164 bytes security) (deflated 66%)

But now that you have the files with file names that contain "paths" with backslashes, you can run the following program in unzip_dir:

#! /usr/bin/env python

# already created directories, walk works topdown, so a child dir
# never creates a directory if there is a parent dir with a file.
made_dirs = set()

for root, dir_names, file_names in os.walk('.'):
    for file_name in file_names:
        if '\\' not in file_name:
            continue
        alt_file_name = file_name.replace('\\', '/')
        if alt_file_name.startswith('/'):
            alt_file_name = alt_file_name[1:]  # cut of starting dir separator
        alt_dir_name, alt_base_name = alt_file_name.rsplit('/', 1)
        print 'alt_dir', alt_dir_name
        full_dir_name = os.path.join(root, alt_dir_name)
        if full_dir_name not in made_dirs:
            os.makedirs(full_dir_name)  # only create if not done yet
            made_dirs.add(full_dir_name)
        os.rename(os.path.join(root, file_name),
                  os.path.join(root, alt_file_name))

This handles files in any directory under the directory from where the program is started. Given the problem that you describe, the unzip_dir probably doesn't have any subdirectories to start with, and the program could just walk over the files in the current directory only.