Got here a list of columns, as follows:
59 LOUIS 1202 +1
60 FREDDIE 1201 +4
61 FINLAY 1200 -2
62 LEON 1137 +12
63 HARLEY 1132 +6
64 DAVID 1127 -1
65 MOHAMMAD1100 +6
66 REECE 1095 -1
67 KIAN 1090 0
68 KAI 1056 -6
69 KYLE 1030 -18
70 BRANDON 1011 -4
71 HAYDEN 1006 +5
72 ZACHARY 995 +10
73 KIERAN 973 -12
73 LUCA 973 -1
75 ASHTON 954 +4
76 BAILEY 939 -6
77 JAKE 913 +10
78 GABRIEL 910 +14
79 SAM 900 -2
80 EVAN 890 0
81 BRADLEY 847 -13
How could be extracted only the lines with, for example, letter "L", as follows:
73 LUCA 973 -1
Best Answer
That seems to be duplicated, but anyway, if it was understood, one may do it as follows:
First, save the list in a some
nameslist.txt
file, then:sed -rn '/^[^\s]+\s+[F]/p' list.txt > result.txt
, which should return following output inresult.txt
file:60 FREDDIE 1201 +4 61 FINLAY 1200 -2