Display lines inbetween text with grep

greptext processing

I know that I can use the -A and -B command for grep to get a lot of what I am looking for however that is not quite what I want.

I am looking to parse the httpd.conf file to search for a domain. Then display everything between the VirtualHost tags for that domain. A example of the virtualhost is as follows.

To search for a domain I run the following command:

less /usr/local/apache2/conf/httpd.conf |grep domain.tld

But that does not give me the full virtualhost only the lines that contain the domain.

<VirtualHost 192.168.1.10:80>
    SSLEngine on
    SSLCACertificateFile /usr/share/ssl/certs/ca-bundle.crt
    SuexecUserGroup anzenketh wheel
    ServerName     anzenketh.net
    ServerAlias    www.anzenketh.net
    ServerAdmin    root@anzenketh.net
    DocumentRoot   /home/anzenketh/www/anzenketh.net
    ScriptAlias    /cgi-bin/ "/home/anzenketh/www/cgi-bin/"
    <Directory /home/anzenketh/www/cgi-bin>
        AllowOverride None
        Options ExecCGI
        Order allow,deny
        Allow from all
    </Directory>
    CustomLog      /var/log/httpd/anzenketh/anzenketh.net-access_log combined
    ErrorLog       /var/log/httpd/anzenketh/anzenketh.net-error_log
</VirtualHost>

Best Answer

Here is a sed call to get everything between (and including) two specific strings:

sed -n '/<VirtualHost*/,/<\/VirtualHost>/p' httpd.conf

If you want to search for a specific domain, just add it:

sed -n '/<VirtualHost 192.168.1.10:80>*/,/<\/VirtualHost>/p' httpd.conf
Related Question