As Vivian suggested, the -t option of ls tells it to sort files by modification time
(most recent first, by default; reversed if you add -r).
This is most commonly used (at least in my experience) to sort the files in a directory,
but it can also be applied to a list of files on the command line.
And wildcards (“globs”) produce a list of files on the command line.
So, if you say
ls -t */file.php
it will list
domain3/file.php domain4/file.php domain2/file.php domain1/file.php
But, it you add the -1 (dash one) option, or pipe this into anything,
it will list them one per line. So the command you want is
ls -t */file.php | sed 's|/file.php||'
This is an ordinary
s/old_string/replacement_string/ substitution in sed,
but using | as the delimiter, because the old_string contains a /,
and with an empty replacement_string.
(I.e., it deletes the filename and the / before it — /file.php —
from the ls output.)
Of course, if you want the trailing / on the directory names,
just do sed 's|file.php||' or sed 's/file.php//'.
If you want, add the -l (lower-case L) option to ls
to get the long listing, including modification date/time.
And then you may want to enhance the sed command
to strip out irrelevant information (like the mode, owner, and size of the file)
and, if you want, move the date/time after the directory name.
This will look into the directories that are in the current directory, and only them.
(This seems to be what the question is asking for.)
Doing a one-level scan of some other directory is a trivial variation:
ls -t /path/to/tld/*/file.php | sed 's|/file.php||'
To (recursively) search the entire directory tree under your current directory
(or some other top-level directory) is a little trickier.
Type the command
shopt -s globstar
and then replace the asterisk (*) in one of the above commands with two asterisks (**), e.g.,
ls -t **/file.php | sed 's|/file.php||'
Best Answer
This can be done in a very simple shell script:
Just loop through each file echoing the name to
wc. The-non theechois so that it doesn't append a newline, which would erroneously increase the count by 1.