Can we print the last word of each line in linux using sed command

awksedtext processing

suppose , if there is a file consisting of following lines , if they are

12345 567 7878 66

   er3   t45t y6y46y 


 4y6 y656y y5y

   46y6 65y7 y66uyuy

 yy46y6y

The output has to look like:

66

y6y46y

y5y

y66uyuyy

y46y6y

I have tried the command sed 's/.* //g' filename and several other sed commands, but it is not working.

Can I know what is the exact sed command?

awk '{print $NF}'
sed 's/[[:blank:]]*$//;s/.*[[:blank:]]//'

That would still print an empty line for every blank line. To avoid it:

awk 'NF{print $NF}'
sed 's/[[:blank:]]*$//;s/.*[[:blank:]]//;/./!d'

Try this:

$ tac infile | sed -n '/fish/,$p' |tac

In general case if you run below sed command, you will get all line from first matched pattern to end of input file.

$ sed -n '/fish/,$p' file

this is a some fish
this is a fishie
this is a fish
this is a lion
this is a cat

So my solution is: If we run tac command on input file your last matched pattern will change to as first pattern. see the result of tac infile:

$ tac infile

this is a cat
this is a lion
this is a fish
this is a fishie
this is a some fish
this is a goat
this is a cow

The tac command is the same as cat command, while tac prints files in reverse order.

Now if we run our first sed command, you will get all lines first matched pattern to end of input file. like:

$ tac infile | sed -n '/fish/,$p'
this is a fish
this is a fishie
this is a some fish
this is a goat
this is a cow

Ok, finished. We only need to run tac command again to reverse back the lines to original order:

$ tac infile | sed -n '/fish/,$p' |tac
this is a cow
this is a goat
this is a some fish
this is a fishie
this is a fish

Done!