input() {
read -p $'\e[31m\e[1m $1 [Y/n] \e[0m' -n 1 -r
}
input "test"
exit
This just prints "$1" in as the line of text. Why isn't it printing "test" and how can I make it do so?
Bash – Why Doesn’t $1 Work Inside $’…’?
bash
bash
input() {
read -p $'\e[31m\e[1m $1 [Y/n] \e[0m' -n 1 -r
}
input "test"
exit
This just prints "$1" in as the line of text. Why isn't it printing "test" and how can I make it do so?
Best Answer
The problem is that variables are not expanded inside single quotes. You are looking for this:
See that only the escape sequences are single quoted now, while
$1is double quoted.