I am trying to do some searching and replacing on a variable using the ${VAR//search/replace} parameter expansion. I have a pretty long and evil PS1, that I want to work out the size of after expansion. To do so I have to remove a bunch of escape sequences I stuff into it. However on trying to remove all the ANSI CSI SGR sequences I've fell across an issue with my syntax.
Given my PS1 of:
PS1=\[\033]0;[\h] \w\007\]\[\033[1m\]\[\033[37m\](\[\033[m\]\[\033[35m\]\u@\[\033[m
\]\[\033[32m\]\h\[\033[1m\]\[\033[37m\]\[\033[1m\])\[\033[m\]-\[\033[1m\](\[\033[m
\]\t\[\033[37m\]\[\033[1m\])\[\033[m\]-\[\033[1m\](\[\033[m\]\[\033[36m\]\w\[\033[1m
\]\[\033[37m\])\[\033[35m\]${git_branch}\[\033[m\]\n$
(yes it's sick I know…)
I'm trying to do:
# readability
search='\\\[\\033\[[0-9]*m\\\]'
# do the magic
sane="${PS1//$search/}"
However these seems to be greedy at the point of [0-9]
(almost like [0-9]
is treated like a .
instead):
echo "${PS1//$search/}"
\[\033]0;[\h] \w\007\]\n$
If I remove the *
, and change [0-9]
to [0-9][0-9]
(as that is more illustrative) I get closer to the expected result:
$ search='\\\[\\033\[[0-9][0-9]m\\\]'
$ echo "${PS1//$search/}"
\[\033]0;[\h] \w\007\]\[\033[1m\](\[\033[m\]\u@\[\033[m\]\h\[\033[1m
\]\[\033[1m\])\[\033[m\]-\[\033[1m\](\[\033[m\]\t\[\033[1m\])\[\033[m\]-\[\033[1m
\](\[\033[m\]\w\[\033[1m\])$(git_branch)\[\033[m\]\n$
Why is the *
(zero or more) doing crazy things? am I missing something here? If I pass the same regex through sed I get the expected result:
echo $PS1 | sed "s/$search//g"
\[\033]0;[\h] \w\007\](\u@\h)-(\t)-(\w)$(git_branch)\n$
Best Answer
Sounds to me you want to remove things between
\[
and\]
:However,
bash
substitution is so inefficient that you would probably be better off firingperl
orsed
here, or do it in a loop like:(that's standard POSIX sh syntax above, BTW).
And if you want the expanded prompt from that: