Is there any way to redirect stdout and stderr via variable like adding command options in script?
For example I have a script:
#!/bin/bash -x
TEST=">/dev/null 2>&1"
OPT='-p -v'
mkdir $OPT 123/123/123 $TEST
I can see that OPT is replaced with -p
without any problems and bash interprets it as option. But redirection interprets as directories name.
$ ./test.sh
+ TEST='>/dev/null 2>&1'
+ OPT='-p -v'
+ mkdir -p -v 123/123/123 '>/dev/null' '2>&1'
mkdir: created directory `123/123'
mkdir: created directory `123/123/123'
mkdir: created directory `>/dev'
mkdir: created directory `>/dev/null'
mkdir: created directory `2>&1'
Is there any way to say bash, that $VAR is redirection, not a dirs names.
PS. May be I'm on wrong way, but I want to make optional verbose or non verbose output from my script. But I need some output even in non-verbose mode, therefore I can't just redirect whole stdout and stderr, only from some commands inside of my script.
Best Answer
Another solution could be the following:
Then add
1>&3 2>&4
only to commands of which you want to see the output.