Bash – Understanding quotes in a bash conditional instruction

For the unquoted example, each \\ pair passes one backslash to grep, so 4 backslashes pass two to grep, which translates to a single backslash. 6 backslashes pass three to grep, translating to one backslash and one \c, which is equal to c. One additional backslash does not change anything, because it is translated \c -> c by the shell. Eight backslashes in the shell are four in grep, translated to two, so this does not match anymore.

For the example in double quotes, note what follows your second quote from the bash manpage:

The backslash retains its special meaning only when followed by one of the following characters: $, `, ", \, or newline.

I.e. when you give an odd number of backslashes, the sequence ends in \c, which would be equal to c in the unquoted case, but when quoted, the backslash looses its special meaning, so \c is passed to grep. That is why the range of "possible" backslashes (i.e. those that make up a pattern matching your example file) slides down by one.

You could do the following using some implementations of find and xargs like this.

$ find . -type f -print0 | xargs -r0 ./myscript

or, standardly, just find:

$ find . -type f -exec ./myscript {} +

Example

Say I have the following sample directory.

$ tree
.
|-- dir1
|   `-- a\ file1.txt
|-- dir2
|   `-- a\ file2.txt
|-- dir3
|   `-- a\ file3.txt
`-- myscript

3 directories, 4 files

Now let's say I have this for ./myscript.

#!/bin/bash

for i in "$@"; do
    echo "file: $i"
done

Now when I run the following command.

$ find . -type f -print0 | xargs -r0 ./myscript 
file: ./dir2/a file2.txt
file: ./dir3/a file3.txt
file: ./dir1/a file1.txt
file: ./myscript

Or when I use the 2nd form like so:

$ find . -type f -exec ./myscript {} +
file: ./dir2/a file2.txt
file: ./dir3/a file3.txt
file: ./dir1/a file1.txt
file: ./myscript

Details

find + xargs

The above 2 methods, though looking different, are essentially the same. The first is taking the output from find, splitting it using NULLs (\0) via the -print0 switch to find. The xargs -0 is specifically designed to take input that's split using NULLs. That non-standard syntax was introduced by GNU find and xargs but is also found nowadays in a few others like most recent BSDs. The -r option is required to avoid calling myscript if find finds nothing with GNU find but not with BSDs.

NOTE: This entire approach hinges on the fact that you'll never pass a string that's exceedingly long. If it is, then a 2nd invocation of ./myscript will get kicked off with the remainder of subsequent results from find.

find with +

That's the standard way (though it was only added relatively recently (2005) to the GNU implementation of find). The ability to do what we're doing with xargs is literally built into find. So find will find a list of files and then pass that list as as many arguments as can fit to the command specified after -exec (note that {} can only be last just before + in this case), running the commands several times if needed.

Why no quoting?

In the first example we're taking a shortcut by completely avoiding the issues with the quoting, by using NULLs to separate the arguments. When xargs is given this list it's instructed to split on the NULLs effectively protecting our individual command atoms.

In the second example we're keeping the results internal to find and so it knows what each file atom is, and will guarantee to handle them appropriately, thereby avoiding the whoie business of quoting them.

Maximum size of command line?

This question comes up from time to time so as a bonus I'm adding it to this answer, mainly so I can find it in the future. You can use xargs to see what the environment's limit like so:

$ xargs --show-limits
Your environment variables take up 4791 bytes
POSIX upper limit on argument length (this system): 2090313
POSIX smallest allowable upper limit on argument length (all systems): 4096
Maximum length of command we could actually use: 2085522
Size of command buffer we are actually using: 131072