Bash – Read from a certain point to a certain character

bashstring

Say I have a file like this:

foo bar foo bar foo bar foo bar something useful"foo bar foo bar"

Basically, I want to know how I can get the string something useful by itself, either saved to its own file or displayed as output alone.

There will always be the same number of characters (33) before something useful and there will always be " directly after it.

Best Answer

Try this:

cut -c 34- | cut -d '"' -f1

First cut removes the first 33 characters; second cut keeps only the part before the first ".

Related Solutions

Bash shell script to locate and remove substring within a filename

Try this:

newname=`echo "$filename" | sed -e 's/\(S[0-9][0-9]E[0-9][0-9]\).*\.mp4/\1.mp4/'`

The regular expression is:

start a group ( \( )
match SXXEXX where X is a numeral between 0 and 9
end group ( \) )
match any number of any character (except a newline)
match a explicit string ( .mp4 )

In the replacement expression:

replace with string matched in first group ( \1 )
replace with explicit string ( .mp4 )

Bash – Is it possible to prepend all terminal output with a certain character

How about this. Starts a new bash process that is piped into awk, where every line piped in gets a couple of spaces printed before $0 (the input line)

$ bash | awk '{print "  " $0}'
$ id
  uid=500(ec2-user) gid=500(ec2-user) groups=500(ec2-user),10(wheel)
$ uname -a
  Linux ip-172-31-37-61 4.9.38-16.33.amzn1.x86_64 #1 SMP Thu Jul 20 01:31:29 UTC 2017 x86_64 x86_64 x86_64 GNU/Linux
$

Best Answer

Related Solutions

Bash shell script to locate and remove substring within a filename

Bash – Is it possible to prepend all terminal output with a certain character

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