Your quoting is wrong. When you write $CMD
with no quotes, the value of $CMD
is broken up into “words” at each whitespace sequence¹ (the words can contain any non-whitespace character including punctuation), and then each word undergoes globbing (i.e. wildcard expansion). Note that quotes in the value of CMD
, in particular, are untouched: quotes have a meaning in the syntax of shell scripts but not in variable substitution. After this, the first word becomes the name of the command to execute, and subsequent words are the command's arguments.
In your example, assuming $KEYNAME
is somekeyname
and $HZID
is somehzid
, then the
command and arguments are:
./dnscurl.pl
--keyname
$KEYNAME
--
-X
POST
-H
"Content-Type:
text/xml;
charset=UTF-8"
--upload-file
/tmp/file.xml
https://route53.amazonaws.com/2010-10-01/hostedzone/somehzid/rrset
Note that text/xml;
appears as the first non-option argument; clearly the Perl script passes that argument down to curl
. The --
in the argument list is unrelated to your problem.
There's no way to stuff a command line into a variable. A (simple) variable is the wrong tool for that: it contains a string, but a command line is a list of strings (the command, and its arguments). You can stuff a command name and its argument into an array variable:
CMD=(./dnscurl.pl --keyname "$KEYNAME" --
-X POST -H "Content-Type: text/xml; charset=UTF-8"
--upload-file /tmp/file.xml
"https://route53.amazonaws.com/2010-10-01/hostedzone/$HZID/rrset")
RESULT=$("${CMD[@]}")
The strange-looking syntax "${CMD[@]}"
expands the array variable CMD
to the list of words in the array. The double quotes prevent expansion of words inside the array, and [@]
is needed for historical reasons to tell the shell that you want to expand an array.
Another way to remember a command line, or an arbitrary shell snippet, for later use, is a function.
cmd () {
./dnscurl.pl --keyname "$KEYNAME" -- \
-X POST -H "Content-Type: text/xml; charset=UTF-8" \
--upload-file /tmp/file.xml \
"https://route53.amazonaws.com/2010-10-01/hostedzone/$HZID/rrset"
}
RESULT=$(cmd)
¹ More precisely, according to the value of IFS
.
"$@"
does exactly what you want provided that you use it consistently. Here's a little experiment for you:
script1.sh
:
#! /bin/sh
./script2.sh "$@"
script2.sh
:
#! /bin/sh
./script3.sh "$@"
script3.sh
:
#! /bin/sh
printf '|%s|\n' "$@"
With this the arguments stay unmolested all the way down:
$ ./script1.sh -i input.m4a -metadata "title=Spaces and \$pecial char's" output.m4a
|-i|
|input.m4a|
|-metadata|
|title=Spaces and $pecial char's|
|output.m4a|
Best Answer
Your shell is not passing the quotes through to the script. If you want to pass quotes, escape them with a backslash: