Bash – Match empty line in an alias .bashrc

To find out what commands are masked by aliases, do something like this:

alias | sed 's/^[^ ]* *\|=.*$//g' | while read a; do
  printf "%20.20s : %s\n" $a "$(type -ta $a | tr '\n' ' ')"
done | awk -F: '$2 ~ /file/'

Explanation

alias alone lists defined aliases and sed extracts their name. The while loop runs type -ta on each of them and awk prints the lines that both contain alias and file.

Use single quotes to suppress processing of special characters. You could also backslash the $s.

For a complex command you are probably better off using a function in any case, which doesn't require any escaping and is easier to read and edit:

svnbranch() {
    svn diff -r $(svn info | grep ^Revision | awk {'print $2'}):HEAD $(svn info | grep ^URL | awk {'print $2'}) | colordiff
}

You can define a function anywhere you could define an alias.