Bash – How to sort results from ls command by modification date (directories first)

My shortest method uses zsh:

print -rl -- **/*(.Om)

(add the D glob qualifiers if you also want to list the hidden files or the files in hidden directories).

If you have GNU find, make it print the file modification times and sort by that. I assume there are no newlines in file names.

find . -type f -printf '%T@ %p\n' | sort -k 1 -n | sed 's/^[^ ]* //'

If you have Perl (again, assuming no newlines in file names):

find . -type f -print |
perl -l -ne '
    $_{$_} = -M;  # store file age (mtime - now)
    END {
        $,="\n";
        print sort {$_{$b} <=> $_{$a}} keys %_;  # print by decreasing age
    }'

If you have Python (again, assuming no newlines in file names):

find . -type f -print |
python -c 'import os, sys; times = {}
for f in sys.stdin.readlines(): f = f[0:-1]; times[f] = os.stat(f).st_mtime
for f in sorted(times.iterkeys(), key=lambda f:times[f]): print f'

If you have SSH access to that server, mount the directory over sshfs on a better-equipped machine:

mkdir mnt
sshfs server:/path/to/directory mnt
zsh -c 'cd mnt && print -rl **/*(.Om)'
fusermount -u mnt

With only POSIX tools, it's a lot more complicated, because there's no good way to find the modification time of a file. The only standard way to retrieve a file's times is ls, and the output format is locale-dependent and hard to parse.

If you can write to the files, and you only care about regular files, and there are no newlines in file names, here's a horrible kludge: create hard links to all the files in a single directory, and sort them by modification time.

set -ef                       # disable globbing
IFS='
'                             # split $(foo) only at newlines
set -- $(find . -type f)      # set positional arguments to the file names
mkdir links.tmp
cd links.tmp
i=0 list=
for f; do                     # hard link the files to links.tmp/0, links.tmp/1, …
  ln "../$f" $i
  i=$(($i+1))
done
set +f
for f in $(ls -t [0-9]*); do  # for each file, in reverse mtime order:
  eval 'list="${'$i'}         # prepend the file name to $list
$list"'
done
printf %s "$list"             # print the output
rm -f [0-9]*                  # clean up
cd ..
rmdir links.tmp

I am not sure what exactly do you mean by update dates, but you are using -r option which according to man does this -

-r Reverse the order of the sort to get reverse lexicographical order or the oldest entries first (or largest files last, if combined with sort by size

I think this should be good enough for you if you need files sorted by time.

ls -lRt

If you don't need all the other stuff listed by ls then you can use -

ls -1Rt

To capture the result in a file, you can use the redirection operator > and give a file name. So you can do something like this -

ls -lRt > sortedfile.list

Update:

find . -type f -exec ls -lt {} +

This will sort files so that the newest files are listed first. To reverse the sort order, showing newest files at the end, use the following command:

find . -type f -exec ls -lrt {} +