I have this code that does work:
get_parameter ()
{
echo "$query" | sed -n 's/^.*name=\([^&]*\).*$/\1/p' | sed "s/%20/ /g"
}
But I want to replace the "name" with the parameter that I pass to get_parameter
get_parameter ()
{
echo "$query" | sed -n 's/^.*$1=\([^&]*\).*$/\1/p' | sed "s/%20/ /g"
}
NAME=$( get_parameter name )
This however, doesn't work. Where am I wrong?
Best Answer
Quoting: In short, variables are not replaced with their values inside
'single-quoted'
strings (aka. "variable substitution"). You need to use any one of"double quotes"
,$'dollar quotes'
, or