Bash – List Only Successfully Run Commands in History

I'm wondering if there's a way to use the history command but only list commands that were run successfully. Likewise, would there be a way to list ones that produced errors?

I know each command has an exit status of:

0 – Successful execution of command
1 – Command fails because of an error during expansion or redirection, the exit status is greater than zero.
2 – Incorrect command usage
12 – Command found but not executable
127 – Command not found

and can be checked proceeding the command with echo $?
from: http://www.linuxnix.com/2011/03/find-exit-status-script-command-linux.html

Example:

After running these 4 commands:

ls
help
lss
ls nonexistentfile

I tried testing to print only successful commands (exit status of 0), which should be only 'ls' and 'help':

for j in `history | tail -5 | head -4 | cut -d ' ' -f5-`; do $j > cmd_out; if [[ `echo $?` != 0 ]]; then :; else echo $j | grep -v 'bash'; fi; done; rm cmd_out

This outputs:

ls
help
bash: lss: command not found
ls
bash: nonexistentfile.txt: command not found

This somewhat works, but there are two problems:

1. For some reason, grep -v 'bash' is not excluding lines containing 'bash', but if I do grep 'bash', it will include only the lines with 'bash', I'm not sure why one works and not the other.
2. It's separating each line/command by string. The last ls command should be
   ls nonexistentfile, but it's running ls and nonexistentfile as separate commands.

Any idea on what I should adjust in the command, or how to go about doing this?