I'm confused with using single or double brackets. Look at this code:
dir="/home/mazimi/VirtualBox VMs"
if [[ -d ${dir} ]]; then
echo "yep"
fi
It works perfectly although the string contains a space. But when I change it to single bracket:
dir="/home/mazimi/VirtualBox VMs"
if [ -d ${dir} ]; then
echo "yep"
fi
It says:
./script.sh: line 5: [: /home/mazimi/VirtualBox: binary operator expected
When I change it to:
dir="/home/mazimi/VirtualBox VMs"
if [ -d "${dir}" ]; then
echo "yep"
fi
It works fine. Can someone explain what is happening? When should I assign double quotes around variables like "${var}"
to prevent problems caused by spaces?
Best Answer
The single bracket
[
is actually an alias for thetest
command, it's not syntax.One of the downsides (of many) of the single bracket is that if one or more of the operands it is trying to evaluate return an empty string, it will complain that it was expecting two operands (binary). This is why you see people do
[ x$foo = x$blah ]
, thex
guarantees that the operand will never evaluate to an empty string.The double bracket
[[ ]]
, on the other hand, is syntax and is much more capable than[ ]
. As you found out, it does not have the "missing operand" issue and it also allows for more C-like syntax with>, <, >=, <=, !=, ==, &&, ||
operators.My recommendation is the following: If your interpreter is
#!/bin/bash
, then always use[[ ]]
It is important to note that
[[ ]]
is not supported by all POSIX shells, however many shells do support it such aszsh
andksh
in addition tobash