I think it's something like this: (Fedora14/bash)
#!/bin/bash
for i in {0..10..1}; do echo -e "$i"'\c'
echo -e "\n\r"
sleep 1
done
But it doesn't work.
Purpose: like this, but without the "clear":
#!/bin/bash
for i in {0..10..1}; do echo -e "$i"
sleep 1
clear
done
So a counting script that doesn't deletes the whole screen to output +1 number, instead it only deletes the line, where the counting is, so that there could be ex.: a beatifull "progress bar"..
Best Answer
You don't need ..1 for stepwidth 1 which is default.
prevents newlines.
\r
is returning to begin of line (without newline -\n
), and better than my formerly used '\b' for backstepping a single character, unhandy, if you have more than one digit-numbers. Thanks to rozcietrzewiacz.