Is there a way to create bash variables and assign them values via a loop?
Something along the lines of:
#!/bin/bash
c=0
for file in $( ls ); do
var"$c"="$file";
let c=$c+1;
done
EDIT: Thank you to @Costas and @mdpc for pointing out this would be a poor alternative to a list; the question is theoretical only.
Best Answer
Well, you absolutely can using eval as follows:
This code will create variables named var0, var1, var2, ... with each one holding the file name. I assume you will have a good reason you want to do that over using an array ...