Ubuntu – Windows filepath converted to Linux filepath

bashcommand linepathstext processing

I have a Windows path in a bash variable as a string:

file='C:\Users\abcd\Downloads\testingFile.log'

I am trying to convert this path into a Linux path starting with /c/Users....

My attempt

The following works:

file=${file/C://c}
file=${file//\\//}
echo $file
> /c/Users/abcd/Downloads/testingFile.log

Problem

Here, I have done this for a string that contains the filepath. The reason I am asking this question is that I have to convert 20 such strings in a bash script in Ubuntu 16.04 and each time I do this I have to write 2 lines per conversion – it is taking up a lot of space!

Question

Is there a way to combine the 2 commands

file=${file/C://c}
file=${file//\\//}

into one command?

Best Answer

There would be a way to do both replacements at once using sed, but it's not necessary.

Here's how I would solve this problem:

Put filenames in array
Iterate over array

filenames=(
  'C:\Users\abcd\Downloads\testingFile.log'
  # ... add more here ...
)

for f in "${filenames[@]}"; do
  f="${f/C://c}"
  f="${f//\\//}"
  echo "$f"
done

If you want to put the output into an array instead of printing, replace the echo line with an assignment:

  filenames_out+=( "$f" )

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Ubuntu – Can you help me to understand this explanation of shell quoting

I've tried to break this down a little bit for you, using your own examples/text as well, check it out:

$ cat fred    
#!/bin/bash

fred='Four spaces between these    words.'

echo "The value of \$fred is $fred"

echo "The next line being printed is simply the results of # echo \$fred"

echo $fred

Running the bash script above prints the following to the terminal/stdout:

The value of $fred is Four spaces between these    words.
The next line being printed is simply the results of # echo $fred
Four spaces between these words.

As well, you can view a terminal video of this here: http://showterm.io/98f56243f60551b338b9f

Ubuntu – How to capture lines between two strings from a file, but only the last occurrence

When I hear "I want to do X with the last something in the file", I think:

reverse the file
do X with the first something in the file
reverse the output of X

In code:

tac logfile | awk '
    BEGIN {text = "ERROR: transfer not complete by end of log file"}
    /^Transfer completed successfully/ {text = ""}
    {text = text ORS $0}
    /^Transfer started at / {print text; exit}
' | tac

Since we are reading the log file from the bottom up, I start with assuming the transfer is not completed. If I see the "transfer completed" message, we can throw out whatever we've captured so far. We save each line. When we see the "transfer started" line, we know we have seen all of the last transfer in the file: print out the (reversed) captured text and exit awk.

Best Answer

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