Ubuntu – Unexpected end of file

bash

Can someone explain why the end of the file is unexpected on line 49? (Line 49 is one line after the last line)

#!/bin/bash 

timeend=$(date -u +%H%M)
timestart=$(date --date "$timeend 30 minutes ago" -u +%H%M)
firsttime=0

while true
do
    if [[ $firsttime -eq 0 ]]; then
    time=$timestart
    increment=0
    fi
    if [[ $firsttime -ne true ]]; then
    increment=$(( $increment + 2 ))
    time=$(( $timestart + $increment ))
    fi
    if [[ $time -ge $timeend ]]; then
    break
    fi 

    gpnids << EOF
    RADFIL   = NEXRIII|CLT|TR0
    RADTIM   = "$time"
    TITLE    = 1/-2
    PANEL    = 0
    DEVICE   = gif|radar"$increment".gif|1280;1024|C
    CLEAR    = Y
    TEXT     = 1/2/2/hw
    COLORS   = 7
    WIND     =  
    LINE     =  
    CLRBAR   =  
    IMCBAR   = 5/v/LL/.005;.6/.4;.01
    GAREA    = dset
    MAP      = 24 + 23 + 1/1/2 + 14 + 15/1/2
    LATLON   = 0
    OUTPUT   = t

    $mapfil = lorvus.usg + hicnus.nws + hipona.nws + louhus.nws + loisus.nws
    run

    exit
    EOF
    firsttime=1

    gpend

 done

Best Answer

You should also have gotten another error which is perhaps more informative:

/home/terdon/scripts/b.sh: line 49: warning: here-document at line 21 delimited by end-of-file (wanted `EOF')

/home/terdon/scripts/b.sh: line 50: syntax error: unexpected end of file

Your error is that you have spaces before the string that ends the heredoc. To take a simple example, this complains:

#!/bin/bash 

cat << EOF
   hello
   EOF

But this doesn't:

#!/bin/bash 

cat << EOF
   hello
EOF

Related Solutions

Ubuntu – “syntax error: unexpected end of file” simple script

There are three obvious errors:

On the line else s=$1-50 m=$2-50 h=$1+1 fi, the word fi is not treated as a keyword, because it is not the first word in the command. To the shell, this looks like three assignments that apply to the command fi. If you ever got to execute this line, you'd see an error bash: fi: command not found. Put fi on a line of its own (or put a ; before it).
[ "$3" < 50 ] is the same as [ "$3" ] < 50 — it's the command [ … ] (which can also be written test) with the sole argument "$3", and with an input redirection from the file 50. Either use the numeric comparison operator -lt, or use an arithmetic instruction (( … )). The single bracket construct is an ordinary built-in command, so special characters such as < retain their normal meaning. The double parenthesis construct is special syntax, and you can use < as a numeric comparison operator inside.
["$2" < 50 ] is missing a space after the opening bracket.

Also the usual convention in shell scripts is to put a newline after then and else. Furthermore, instead of an else block that consists entirely of an if statement, you should use elif. And please indent consistently.

#!/bin/bash
declare -i s
declare -i m
declare -i h

if (( $3 < 50 )); then
  s=$3+10  m=$2  h=$1
elif (( $2 < 50 )); then
  s=$3-50  m=$2+1  h=$1
else
  s=$1-50  m=$2-50  h=$1+1
fi 

echo "$h:$m:$s"

P.S. I haven't reviewed your logic. You seem to be looking for date +%T -d 'now + 10 seconds'.

Ubuntu – unexpected end of file bashrc

Your problem is line 93:

alias ll='ls -alF

You're missing the closing quote ('). That should be:

alias ll='ls -alF'

The error you are getting is confusing because bash sees the opening ' and then tries to find a closing one, and that confuses its parser completely. Just fix the missing ' there and you should be fine.

It is complaining about line 120 because it searches all the way to the end of the file (so last line + 1) and doesn't find its closing quote.

Best Answer

Related Solutions

Ubuntu – “syntax error: unexpected end of file” simple script

Ubuntu – unexpected end of file bashrc

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