Ubuntu – Store output of command into the array

I would do this just using bash itself:

#!/bin/bash
read -e -p 'Enter the string: ' post
declare -A myArr

while IFS='&' read name age; do
    myArr["${name##*=}"]="${age##*=}"
done <<<"$post"

printf 'NAME: %s, AGE: %s\n' "${!myArr[@]}" "${myArr[@]}"

Here is what i get in the output:

Enter the string: name=Foo Bar&age=40
NAME: Foo Bar, AGE: 40

• The input string is spitted on & using IFS environmental variable

• The name and age values are parsed using parameter expansion pattern ${var##*=}

• You can get all keys using ${!myArr[@]} and all values using ${!myArr[@]}

In practice, I don't think you would just make an associative array of one element. If you have multiple elements, replace the last printf line with a simple for construct to loop over the keys:

for key in "${!myArr[@]}"; do
    printf 'NAME: %s, AGE: %s\n' "$key" "${myArr["$key"]}"
done

First, you need to remove the text from around the assignment of the string variable:

text="'xdc','cde','erd','ded','ded','kie';"

Then you can just use the array form of the bash read command:

IFS=, read -a ids <<< "${text%;}"

where the ${text%;} substitution removes the trailing semicolon. Note that, this way, the IFS is not modified outside of the read command so there's no need to save and restore it.

Your C-style for-loop syntax is almost correct, except that in bash, the loop needs double parentheses e.g.

for ((i=0; i<${#ids[@]}; ++i)); do printf '%s\n' "${ids[i]}"; done

Alternatively, you can loop over array members directly using a for ... in loop:

for i in "${ids[@]}"; do printf '%s\n' "$i"; done